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Misc optimizations that address some of the XXX
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#202
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6dfb60e
temp changes
linxuanm cb2fdea
misc XXX fixes
linxuanm b117fc3
binary search lookups for performance
linxuanm d277935
more binary searches + range
linxuanm a84e048
SidetableMap build array on new()
linxuanm 5505320
Rename: VectorUtil -> RangeUtil
linxuanm 04a7a9e
Binary search works
linxuanm 7b1f324
Used the new pushr
linxuanm b63bbae
Addressed some minor fixes
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Original file line number | Diff line number | Diff line change |
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// Copyright 2020 Ben L. Titzer. All rights reserved. | ||
// See LICENSE for details of Apache 2.0 license. | ||
|
||
// Utility methods for vector. | ||
// | ||
// TODO: all these searches can be done on Range<T>. Maybe add a `toRange` | ||
// method to `Vector` in virgil and change this to `RangeSearchUtil`? Vector<T> | ||
// to Range<T> should be pretty much free. | ||
component RangeUtil { | ||
// Assumes that the vector is sorted. | ||
def binarySearch<T>(range: Range<T>, val: T, lt: (T, T) -> bool) -> int { | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. I like this method. I think it should live in Virgil's |
||
var l = 0, r = range.length; | ||
while (l < r) { | ||
var mid = (l + r) >> 1; | ||
var mid_val = range[mid]; | ||
if (lt(val, mid_val)) r = mid - 1; | ||
else if (lt(mid_val, val)) l = mid + 1; | ||
else return mid; | ||
} | ||
return -1; | ||
} | ||
// Returns the *first* element that is *not less* than `val`. | ||
def lowerbound<T>(range: Range<T>, val: T, lt: (T, T) -> bool) -> int { | ||
var start = 0; | ||
var count = range.length; | ||
while (count > 0) { | ||
var step = count >> 1; | ||
var mid = start + step; | ||
if (lt(range[mid], val)) { start = mid + 1; count -= step + 1; } | ||
else count = step; | ||
} | ||
return start; | ||
} | ||
// Returns the *first* element that is *greater* than `val`. | ||
def upperbound<T>(range: Range<T>, val: T, lt: (T, T) -> bool) -> int { | ||
var start = 0; | ||
var count = range.length; | ||
while (count > 0) { | ||
var step = count >> 1; | ||
var mid = start + step; | ||
if (!lt(val, range[mid])) { start = mid + 1; count -= step + 1; } | ||
else count = step; | ||
} | ||
return start; | ||
} | ||
} |
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If you're looking for an exact match, I think it makes sense to have a utility method that specifically finds an exact match.