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Classify depth-four chain connector count vectors and unequal-price tariffs for m = 2..5 (no new κ) - #4279
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Mister-Meeseeks merged 1 commit intoOct 21, 2026
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Every correct count vector is a multiple of m dominating a listed Pareto vector, for words of any length. At m = 2, 3, 4 the premium falls only on the two middle calls; at m = 5 any single call can be doubled.
This was referenced Oct 21, 2026
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Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
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Result
Exact call-count classification and unequal-price tariff for the unsigned depth-four dirty chain connector in characteristics 2 to 5, for every nonzero target residue and for words of any length.
The calls are
z_l += B_l z_{l-1}for l = 1..4. The source x = z_0 is immutable, z_1..z_3 and y = z_4 start dirty, and the maps are arbitrary. A correct word restores z_1..z_3 and addsc B4B3B2B1 xto y. A count vector (n1,n2,n3,n4) is feasible if and only if every n_l is a multiple of m and it dominates a member ofThe set does not depend on c. With positive complete-call prices and S = p1+p2+p3+p4, the cheapest bill is
At unit prices these are #4249's lengths 12, 18, 20, 25. What is new is where the premium sits. At m = 2, 3, 4 it falls only on the two middle operations: no minimal word doubles the first or last call, however cheap those calls are. At m = 5 any one call can be doubled. For 6 <= m <= 32 the bill is mS, a corollary of #4263's balanced witnesses (cited, not rechecked).
Claim type: scoped proof whose completeness step is a finite reduction checked by computer, plus a finite certificate for each witness. No new κ, no supplier admission and no selected-frontier change.
The key step: a 1 matters only through which 2s follow it, and a 4 only through which 3s precede it. So every interval count is a function of the order of the 2s and 3s, the prefix counts u of 1s and the suffix counts r of 4s, with N14 = u'Ar for the precedence matrix A. Leaving n1 and n4 free lets u and r range over all residue vectors. At m = 3, 4 that relaxation reaches no nonzero target on any middle pair the Pareto set misses. This covers words of every length. m = 2 has a short hand proof (two 2s force N14 = u1·N24 = 0), and m = 5 needs only the exact exclusion of (5,5,5,5).
Only
research/depth4-chain-tariff/is added, on base12fa8c5c844be21bfefb38a19503fbd867a11244(priority revision 7, cardconnector-alphabet-change, scope explicitly changed in TASK.json).Evidence and reproduction
From the repository root:
Locally (CPython 3.12, macOS arm64), both registered commands print
PASS_DEPTH4_CHAIN_TARIFF witnesses=29 replays=87 box_comparisons=125 cross_checks=116 receipt_sha256=42f5bef2…in about 57 s each. The receipt is generated and bound to every package file and source input hash.PASS_REGISTERED_RESEARCH_PACKAGEandPASS_RESEARCH_COMMIT_BYTESpass.The verifier is standard-library only. It checks:
The witnesses came from a seeded local annealing search that is not packaged. The verifier checks the words themselves.
Limitations and unrun obligations
Only m = 2..5 is proved. The mS corollary for larger m is a cited statement: #4263 (open, not rechecked) covers 6 <= m <= 32 and #4280 (open, not rechecked) covers 33 <= m <= 64, so it extends to 6 <= m <= 64. m >= 65 remains open. Word multiplicities at the Pareto vectors are not counted. Independent human and formal proof-kernel review are unclaimed. Every call carries its complete price. Admission, dispatch, routing of the three dirty intermediates, precision, stock, supplier caller and the outer multiplication theorem are not supplied.
Open next questions
Related open work
CI notes
Hosted CI is green on head
bb56c7c1681a743acb6eeb9057563211a8498905: run 39525253988.planpassed in 2m43s and the packagereplayin 7m12s. No check failed. Locally each registered command takes about 1 minute.Produced by Nick Petalas. Predecessor credit: #4249, #4257, #4263 and Ross Richardson's #943/#934 connector lineage. Apache-2.0.