0131.分割回文串：Swift实现优化迭代中跳过逻辑

xjtuchenchao · Dec 23, 2021 · 690897f · 690897f
1 parent 622b443
commit 690897f
Showing 1 changed file with 3 additions and 6 deletions.
diff --git a/problems/0131.分割回文串.md b/problems/0131.分割回文串.md
@@ -575,12 +575,9 @@ func partition(_ s: String) -> [[String]] {
 
         for i in startIndex ..< s.count {
             // 回文则收集，否则跳过
-            if isPalindrome(start: startIndex, end: i) {
-                let substring = String(s[startIndex ... i])
-                path.append(substring)
-            } else {
-                continue
-            }
+            guard isPalindrome(start: startIndex, end: i) else { continue }
+            let substring = String(s[startIndex ... i])
+            path.append(substring) // 处理
             backtracking(startIndex: i + 1) // 寻找下一个起始位置的子串
             if !path.isEmpty { path.removeLast() } // 回溯
         }