CycleSolver

Package for solving steady state thermodynamic cycles
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How to install · How to cite this project · See examples

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The CycleSolver.jl package uses metaprogramming to provide a unique formatting structure for representing cycles and supplying already known properties. Based on this, the algorithm seeks to automatically discover other unknown properties of the system.

In addition to cycle solving, the presented package also offers result visualization features, generating tables and graphs to clearly illustrate cycle properties. This way, the tool allows for a quick and reliable analysis of thermodynamic cycles.

Installation

To install CycleSolver.jl, use the Julia package manager. In Julia REPL, type ] to enter Pkg REPL mode and run:

pkg> add CycleSolver

Alternatively, you can install it via the Pkg API:

julia> using Pkg

julia> Pkg.add("CycleSolver")

Additionally, you have the option to use the CycleSolver.jl package in an online environment, without the need for any local software installation. You can access it through the following link:

• CycleSolver Online

Documentation

For information on how to use the package, see the documentation.

Citations

How to cite this project:

@Misc{2023-FilipakiV-CycleSolver,
  author       = {V. Filipaki},
  title        = {{CycleSolver.jl} -- Solver for thermodynamic cycles},
  howpublished = {Online},
  month        = {August},
  year         = {2023},
  journal      = {GitHub repository},
  publisher    = {GitHub},
  url          = {https://github.com/vFilipaki/CycleSolver.jl},
}

Example

Cycle data - Ideal Simple Rankine Cycle
Known properties:
> Temperature at the boiler outlet 250 °C; > Pressure before turbine 1000 kPa; > Pressure after turbine 10 kPa.

Input code

using CycleSolver

@solve begin
    st3.T = 250 + 273
    st3.p = 1000
    st1.p = 10

    newCycle[]
        pump(st1, st2)
        boiler(st2, st3)
        turbine(st3, st4)
        condenser(st4, st1) 
end

PrintResults()

Output:

1- CYCLE [water]

State Name	T [K]	P [kPa]	h [kJ/kg]	s [kJ/kg.K]	x	ṁ [kg/s]	Mass-flux fraction
st1	318.956	10.0	191.806	0.6492	0.0		1.0
st2	318.989	1000.0	192.806	0.6492			1.0
st3	523.0	1000.0	2942.79	6.9258			1.0
st4	318.956	10.0	2193.78	6.9258	0.8369		1.0

Cycle Properties:

	Total	Component	Value
qin Q̇in	2749.9849 kJ/kg 0.0 kW	boiler: st2 >> st3	2749.9849 kJ/kg
qout Q̇out	2001.9783 kJ/kg 0.0 kW	condenser: st4 >> st1	2001.9783 kJ/kg
win Ẇin	1.0 kJ/kg 0.0 kW	pump: st1 >> st2	1.0 kJ/kg
wout Ẇout	749.0066 kJ/kg 0.0 kW	turbine: st3 >> st4	749.0066 kJ/kg

Thermal efficiency (n) = 27.2004 %