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phrase = 'fizz and buzz';
}

console.log( phrase );

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Outside the function ;-)
Here: return phrase

}

function init(){
playFizzBuzz();

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Here: console.log(playFizzBuzz) ;-)

return;
}

init();

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In general, I advise not to complicate the solution and to solve it with at most three conditions.

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Hi,
can you kindly check that everything is ok now and resolve the pr?

Thank you.

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Hi, I made the changes for all comments, thank you.

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This algorithm does not solve the problem correctly.
But at this point, I suggest you not change the code now.
Write the tests first and see if it really works as you would expect or not.
In short, correct it after testing it ;-)

…tants and the direct printing of value in exercise 024
phrase = 'fizz';
} else if ( i % 5 === 0){
phrase = 'buzz';
} else if ( i % 3 === 0 && i % 5 === 0){

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Will this code ever run? ;-)

let phrase = i;

if ( i % 3 === 0 ){
phrase = 'fizz';

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Hint: phrases += 'fizz' + '\n';

const length = 100;

for (let i = 1; i <= length; i++) {
let phrase = i;

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The use of this additional variable phrase is not recommended.


}

phrases += i === length ? phrase : phrase + '\n';

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This check is also not recommended.
It makes no sense to check 100 values ​​to remove the trailing '\n'.
Find a workaround to remove it ;-)

…meric value if the previous conditions are not satisfied, remove useless constant and variable, used replace function for phrases to remove last n occurence in exercise 024
return;
}

init();

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This algorithm does not solve the problem correctly.
But at this point, I suggest you not change the code now.
Write the tests first and see if it really works as you would expect or not.
In short, correct it after testing it ;-)

… remainder 3 and 5 equal to 0 for first. added the test file to check if the function playFizzBuzz works correctly in exercise 024
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2 participants