wraps() fails when wrapped function is a lambda

[andrewcleveland]

Currently, it's not possible to do @wraps(f) when f is a lambda function:

from makefun import wraps

def wrap_times_two(f):
    @wraps(f)
    def wrapper(a):
        return f(a) * 2
    return wrapper

times_two = wrap_times_two(lambda a: a)

fails with:

Error in generated code:
def <lambda>(a):
    return _func_impl_(a=a)

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 3, in wrap_times_two
  File "/home/andy/.local/lib/python3.10/site-packages/makefun/main.py", line 954, in replace_f
    return create_function(func_signature=func_signature,
  File "/home/andy/.local/lib/python3.10/site-packages/makefun/main.py", line 267, in create_function
    f = _make(func_name, params_names, body, evaldict)
  File "/home/andy/.local/lib/python3.10/site-packages/makefun/main.py", line 629, in _make
    code = compile(body, filename, 'single')
  File "<makefun-gen-0>", line 1
    def <lambda>(a):
        ^
SyntaxError: invalid syntax

Resolved by #80.
If that's not the right way to go, then it would be helpful to throw an error explaining that lambda functions aren't allowed.

Thanks.