Quoted match on an exported definition? (matching the "original" definition)

[deusaquilus]

Compiler version

Latest Nightly: scala-3.0.2-RC1-bin-20210626-f33bc8d-NIGHTLY

Minimized code

Create a global function in a namespace (e.g. Dsl). Then export it:

package io.getquill.mytest

object Dsl:
  def stuff: String = ???

export Dsl._

Then make a quoted-match clause to match it:

object ParseMacro:
  inline def parse(inline any: Any): Unit = ${ parseImpl('any) }
  def parseImpl(any: Expr[Any])(using Quotes): Expr[Unit] =
    import quotes.reflect._
    any match
      case '{ Dsl.stuff } => println("Matched!")
      case _ => println("Did not match")
    '{ () }

Then use the macro to match it based on the export:

import mytest._
ParseMacro.parse(stuff)

It will not match.

Output

The clause does not match i.e. Did not match is printed.

Expectation

The clause should match the exported symbol.

Repo

Example code can be found here:
https://github.com/deusaquilus/export_match_issue

[deusaquilus]

Note that this is a serious issue. If you have dozens of functions defined in the Dsl object and want them to be exported up to the package-level, you literally have to repeat every single quoted-match clause twice. I.e:

For this:

object Dsl:
  def stuff: String = ???
  def otherStuff: String = ???
  def otherOtherStuff: String = ???

Need to do this:

    any match
      case '{ Dsl.stuff } => println("Matched!")
      case '{ Dsl.otherStuff } => println("Matched!")
      case '{ Dsl.otherOtherStuff } => println("Matched!")
      case '{ stuff } => println("Matched!")
      case '{ otherStuff } => println("Matched!")
      case '{ otherOtherStuff } => println("Matched!")

[bishabosha]

exports create forwarder methods, so stuff is simply unrelated to Dsl.stuff, just like if you declared two methods in different namespaces that share the same name. So I am recording this as intended behaviour.

[deusaquilus]

@bishabosha However you choose to classify it, this is still a significant problem. It basically means that quoted-dsls can never be exported unless the writer of the parser is willing to reproduce all of the match-clauses over and over again (let alone the fact that this behavior is extremely unintuitive).

[bishabosha]

We already have some de-virtualisation for overridden methods in quotes, so it could be worth exploring (following exports to their original definition) @nicolasstucki ?

currently there is no efficient compiler machinery for this but it is possible to implement your own reverse map for exported definitions by checking for a symbol ref, where that ref has the Exported flag, and then you follow the return type of that definition, or its rhs, to find where that export was defined in. Theres an example of using TastyInspector to do this in scaladoc: https://github.com/lampepfl/dotty/blob/f33bc8df9bbdabb921fe70b0d136cb3fd4f25355/scaladoc/src/dotty/tools/scaladoc/tasty/ClassLikeSupport.scala#L137

[odersky]

I think that touches quoting more than exports. Should patterns in quotes be able to see through aliases? I am not sure about this.