fix Range examples. remove Range.ByOne

ja/overviews/collections/concrete-immutable-collection-classes.md

@@ -134,16 +134,14 @@ first in first out) だ。
 範囲 ([`Range`](http://www.scala-lang.org/api/{{ site.scala-version }}/scala/collection/immutable/Range.html)) は順序付けされた等間隔の整数の列だ。例えば、「1、2、3」は範囲であり、「5、8、11、14」も範囲だ。Scala で範囲を作成するには、予め定義された `to` メソッドと `by` メソッドを使う。
 
     scala> 1 to 3
-    res2: scala.collection.immutable.Range.Inclusive
-      with scala.collection.immutable.Range.ByOne = Range(1, 2, 3)
+    res2: scala.collection.immutable.Range.Inclusive = Range(1, 2, 3)
     scala> 5 to 14 by 3
     res3: scala.collection.immutable.Range = Range(5, 8, 11, 14)
 
 上限を含まない範囲を作成したい場合は、`to` の代わりに、便宜上用意された `until` メソッドを使う:
 
     scala> 1 until 3
-    res2: scala.collection.immutable.Range.Inclusive
-      with scala.collection.immutable.Range.ByOne = Range(1, 2)
+    res2: scala.collection.immutable.Range = Range(1, 2)
 
 範囲は、開始値、終了値、ステップ値という、たった三つの数で定義できため定数空間で表すことができる。そのため、範囲の多くの演算は非常に高速だ。
 

overviews/collections/concrete-immutable-collection-classes.md

@@ -133,16 +133,14 @@ Note that `dequeue` returns a pair consisting of the element removed and the res
 A [Range](http://www.scala-lang.org/api/{{ site.scala-version }}/scala/collection/immutable/Range.html) is an ordered sequence of integers that are equally spaced apart. For example, "1, 2, 3," is a range, as is "5, 8, 11, 14." To create a range in Scala, use the predefined methods `to` and `by`.
 
     scala> 1 to 3
-    res2: scala.collection.immutable.Range.Inclusive
-      with scala.collection.immutable.Range.ByOne = Range(1, 2, 3)
+    res2: scala.collection.immutable.Range.Inclusive = Range(1, 2, 3)
     scala> 5 to 14 by 3
     res3: scala.collection.immutable.Range = Range(5, 8, 11, 14)
 
 If you want to create a range that is exclusive of its upper limit, then use the convenience method `until` instead of `to`:
 
     scala> 1 until 3
-    res2: scala.collection.immutable.Range.Inclusive
-      with scala.collection.immutable.Range.ByOne = Range(1, 2)
+    res2: scala.collection.immutable.Range = Range(1, 2)
 
 Ranges are represented in constant space, because they can be defined by just three numbers: their start, their end, and the stepping value. Because of this representation, most operations on ranges are extremely fast.
 

tutorials/FAQ/collections.md

@@ -229,7 +229,6 @@ it. Also available are some traits with further refinements, such as
 
 			* `immutable.Range` -- A delimited sequence of integers, closed on the lower end, open on the high end, and with a step.
 				* `immutable.Range.Inclusive` -- A `Range` closed on the high end as well.
-				* `immutable.Range.ByOne` -- A `Range` whose step is 1.
 			* `immutable.NumericRange` -- A more generic version of `Range` which works with any `Integral`.
 				* `immutable.NumericRange.Inclusive`, `immutable.NumericRange.Exclusive`.
 				* `immutable.WrappedString`, `immutable.RichString` -- Wrappers which enables seeing a `String` as a `Seq[Char]`, while still preserving the `String` methods. I'm not sure what the difference between them is.

zh-cn/overviews/collections/concrete-immutable-collection-classes.md

@@ -130,16 +130,14 @@ Vector结构通常被表示成具有高分支因子的树（树或者图的分
 [Range]表示的是一个有序的等差整数数列。比如说，“1，2，3，”就是一个Range，“5，8，11，14，”也是。在Scala中创建一个Range类，需要用到两个预定义的方法to和by。
 
     scala> 1 to 3
-    res2: scala.collection.immutable.Range.Inclusive
-      with scala.collection.immutable.Range.ByOne = Range(1, 2, 3)
+    res2: scala.collection.immutable.Range.Inclusive = Range(1, 2, 3)
     scala> 5 to 14 by 3
     res3: scala.collection.immutable.Range = Range(5, 8, 11, 14)
 
 如果您想创建一个不包含范围上限的Range类，那么用until方法代替to更为方便：
 
     scala> 1 until 3
-    res2: scala.collection.immutable.Range.Inclusive
-      with scala.collection.immutable.Range.ByOne = Range(1, 2)
+    res2: scala.collection.immutable.Range = Range(1, 2)
 
 Range类的空间复杂度是恒定的，因为只需要三个数字就可以定义一个Range类：起始、结束和步长值。也正是因为有这样的特性，对Range类多数操作都非常非常的快。