Closed
Description
A super.foo
call in a trait will require a super-accessor in every class that implements the trait since the super will be resolved based on the linearization order of the class. In most cases this is probably not what you want, e.g. in https://github.com/scala/scala/blob/d6455592055ce1729ab7ac11d69da3a5a5f3d9dc/src/library/scala/collection/Seq.scala#L187
I suspect what you really meant was:
super[IterableOps].concat(suffix)
Besides possible unwanted semantics and performance impact, super-accessors are also problematic because they cannot always be implemented (this is now detected as of scala/scala3#5604 / scala/scala3#5604), so I think it's worht reviewing their use before RC1 ships since adding or removing super-accesors is binary-incompatible.