inconsistencies of .subs() for multivariate polynomials

[videlec]

sage: R.<x,y,z> = ZZ[]
sage: x.subs({x:1}).parent()
Multivariate Polynomial Ring in x, y, z over Integer Ring
sage: x.subs({x:1, y:1, z:1}).parent()
Multivariate Polynomial Ring in x, y, z over Integer Ring

compared to the univariate case

sage: R.<t> = ZZ[]
sage: t.subs({t:1}).parent()
Integer Ring

Note also that we have

sage: x.subs({x:RDF(1)}).parent()
Real Double Field

CC: @sagetrac-tmonteil @bgrenet

Component: algebra

Issue created by migration from https://trac.sagemath.org/ticket/19130

[mantepse]

See https://groups.google.com/g/sage-devel/c/vGzNJKAQWbs/m/YBRN4XOjAwAJ for some discussion.

[mantepse]

There seems to be consensus that, ideally, the parent of the output should only depend on the parents of the input.

A further question is, whether one should make a distinction between a partial substitution, i.e., where only some of the generators are substituted, and a full substitution.

One idea is to regard any partial substitution as a full substitution, where unspecified generators are substituted by themselves.

Then, the parent of the output could be the common parent of base ring and parents of the values. Doing so,

sage: R.<x,y,z> = ZZ[]
sage: x.subs({x:1}).parent()
Multivariate Polynomial Ring in x, y, z over Integer Ring

would be correct. By contrast, we would have

sage: R.<x,y,z> = ZZ[]
sage: x.subs({x:1, y:0, z:0}).parent()
Integer Ring

By analogy, substitutions in the InfinitePolynomialRing would always be partial.

@tscrim, @nbruin, @videlec, @novoselt, what do you think?

[mantepse]

However, the following doctests violates the proposed rule:

            sage: P = QQ['x,y']
            sage: x = var('x')                                                          # needs sage.symbolic
            sage: parent(P.zero().subs(x=x))                                            # needs sage.symbolic
            Symbolic Ring

Here, the substitution is partial, so given the above the result should be in Multivariate Polynomial Ring in x, y over Symbolic Ring. (Maybe replacing SR with QQbar would make a better example.)

One might argue that constants are special, but it seems that only zero is treated specially:

sage: R.<x,y> = QQ[]
sage: R(0).subs({x:QQbar(sqrt(2))}).parent()
Algebraic Field
sage: R(1).subs({x:QQbar(sqrt(2))}).parent()
Rational Field

[mantepse]

Possibly this question should be discussed together with what the parent of the result of division should be. Currently, we have

sage: R.<x,y> = QQbar[]
sage: (x/R(2)).parent()
Multivariate Polynomial Ring in x, y over Algebraic Field

sage: R.<x> = QQbar[]
sage: (x/R(2)).parent()
Fraction Field of Univariate Polynomial Ring in x over Algebraic Field

[tscrim]

In some ways this is more clear cut, but we do have some exceptions for very important reasons (mainly Laurent polynomials when dividing by a monomial). Whichever way we decide to do it, we should 100% be consistent between the uni- and multi-variate cases.

I don’t like that 0 is treated differently than constants. At the very least I expect those to behave the same.

[nbruin]

I like the idea of filling up a partial substitution to a full one. Hopefully that is not incompatible with other cases.
However, isn't that a bit impractical for infinite polynomial rings? How would you "fully evaluate" an infinite polynomial ring member? Are these just not evaluable? (perhaps they are not. Perhaps one should first coerce them into a polynomial ring with all the variables that actually occur and evaluate them from there ... or can you only get an outright full evaluation if you pass it an infinite sequence?)

[mantepse]

Yes, there would be no full evaluation of InfinitePolynomial. And I should also have said that this would only be the definition, not the implementation.

[novoselt]

My main point on such issues is that it is extremely frustrating when there are discrepancies between univariate and multivariate behaviour, as well as different "special" cases like 0 and 1 demonstrated here. When the code is written to treat one case and then suddenly it breaks on another, which is logically the same, it is unpleasant. Since you can substitute elements that will expand the ring, it is natural to expect some changes. But when such a change is happening for a particular substitution, there is no reason to depend on the polynomial. In particular, maybe there is usually a substitution into "a full polynomial", but in some case it happens to be 0. That zero should work in the same way after the substitution, without any surprises with smaller rings.