Partition().to_exp() should return Sage Integers

[jdemeyer]

sage: e = Partition([2,1,1]).to_exp()
sage: e
[2, 1]
sage: [type(x) for x in e]
[<type 'int'>, <type 'int'>]

Note: as Volker points out in comment [comment:1], there are more places with the same problem. Since this ticket is intended to avoid a doctest failure in #17130, I only fixed this one instance.

Component: combinatorics

Author: Jeroen Demeyer

Branch/Commit: 24020fe

Reviewer: Volker Braun

Issue created by migration from https://trac.sagemath.org/ticket/17133

[vbraun]

comment:1

Thats really a pattern that is all over the combinatorics stuff:

sage: iter(Partitions(4)).next()[0]
4
sage: type(_)
<type 'int'>

or

sage: g = SymmetricGroup(3).gen(0)
sage: type(g(1))
<type 'int'>

I've tripped more than once over this, its really common to want to do n.factorial() for some integer from a partition.

[jdemeyer]

Description changed:

--- 
+++ 
@@ -6,3 +6,5 @@
 sage: [type(x) for x in e]
 [<type 'int'>, <type 'int'>]
 ```
+
+Note: as Volker points out in comment [comment:1], there are more places with the same problem. Since this ticket is intended to avoid a doctest failure in #17130, I only fixed this one instance.

[jdemeyer]

Branch: u/jdemeyer/ticket/17133

[vbraun]

Reviewer: Volker Braun

[vbraun]

New commits:

24020fe

Partition().to_exp() should return Sage Integers

[vbraun]

Commit: 24020fe

[vbraun]

Changed branch from u/jdemeyer/ticket/17133 to 24020fe