Description
If you have an argument with a default_value:
, and the argument is not visible for some reason, then the key (and thus default value) is not even present in the arguments hash. This is logically correct, but has caught us in a bug a couple of time where somebody will write, e.g.
argument :foo, Boolean, required: false, default_value: true, public: false
def resolve(**args)
if args[:foo]
# ...
end
end
And then the wrong branch will execute when somebody runs against the public schema (i.e. with foo
not visible) because it will be nil and interpreted as false
instead of the desired "default" of true
.
The current behaviour is correct/coherent, and there are a couple of obvious ways around this (e.g. listing out all of the args as kwargs to the resolve method, which requires duplicating all the default values and is annoying). But I wanted to ask in case anybody has a better pattern for avoiding this, or if the description of the problem prompts a clever idea for a solution.
It may not be spec-compliant / probably causes just as many problems as it solves, but injecting the default value even for invisible arguments is kind of the most "obvious" solution here.