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bpo-32984: IDLE - set __file__ for startup files #5981

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Mar 5, 2018
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bpo-32984: IDLE - set __file__ for startup files #5981

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bpo-32984: IDLE - set __file__ for startup files
terryjreedy Mar 5, 2018
97439a8
add blurb
terryjreedy Mar 5, 2018
96696db
Apply Cheryl's code fix and markup.
terryjreedy Mar 5, 2018
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3 changes: 3 additions & 0 deletions Lib/idlelib/pyshell.py
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Original file line number Diff line number Diff line change
Expand Up @@ -635,6 +635,9 @@ def execfile(self, filename, source=None):
if source is None:
with tokenize.open(filename) as fp:
source = fp.read()
if use_subprocess:
source = (f"__file__ = r'''{os.path.abspath(filename)}'''\n"
+ source + "\ndel __file__")
try:
code = compile(source, filename, "exec")
except (OverflowError, SyntaxError):
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7 changes: 7 additions & 0 deletions Misc/NEWS.d/next/IDLE/2018-03-05-01-29-05.bpo-32984.NGjgT4.rst
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@@ -0,0 +1,7 @@
Set ``__file__`` while running a startup file. Like Python, IDLE optionally
runs one startup file in the Shell window before presenting the first interactive
input prompt. For IDLE, ``-s`` runs a file named in environmental variable
:envvar:`IDLESTARTUP` or :envvar:`PYTHONSTARTUP`; ``-r file`` runs
``file``. Python sets ``__file__`` to the startup file name before running the
file and unsets it before the first prompt. IDLE now does the same when run
normally, without the ``-n`` option.