How to convert PDF to image, using the original document settings for the image size and set to 300dpi?

[AddEleven]

Hi,

I'm currently looking at using PyMuPDF for a workflow that converts PDF's to images (In my case, .TIFF files).

I am trying to mimic the behaviour of another program that I currently use for PDF -> Image conversion. In that program, it lets you set the settings for imaging as below:
Image Output Quality (DPI): (Defaults to 300dpi)
Basic Image Size: Original setting - renders the image with the original document settings.

My question is, is this possible within PyMuPDF? How can I set the output DPI for my images to 300 and set the image size to the original document size? I am quite new to dealing with this sort of processing for PDF's/images so any help would be much appreciated.

Thanks in advance,

[JorjMcKie]

Sounds like you will create a so-called "pixmap" for each page and save that as an image.
PyMuPDF itself only support a handful of image output formats, the most popular being PNG, others are the PNM-type images.
If you want to use others, you must use an additional package, presumably PIL/Pillow.
PyMuPDF supports Pillow directly via its pixmap output methods.
So a code snippet may look like this:

import fitz
mat = fitz.Matrix(300 / 72, 300 / 72)  # sets zoom factor for 300 dpi
doc = fitz.open("yourfile.pdf")
for page in doc:
    pix = page.get_pixmap(matrix=mat)
    img_filename = "page-%04i.tiff" % page.number
    pix.pil_save(img_filename, format="TIFF", dpi=(300,300), ... more PIL parameters)

For more sophistication on PIL output, please consult their documentation. For example, TIFF supports multiple images in one file.

[AddEleven]

Hi @JorjMcKie,

Thanks for the solution, I believe this will be what I need to get it working.
Could I just ask, what does the number 72 represent in this situation and will my matrix always be 300 / 72

Thanks,

[JorjMcKie]

1 inch are 72 points, the standard dpi, which you therefore have to multiply by 300/72 to achieve 300 dpi.