Template rendering fails by default

[one4many]

In backend.py you blindly do this: template = loader.get_template(self.template)
This fails per default with the current django_flilters package.
django_filters defines template as 'django_filters/rest_framework/form.html' (or 'django_filters/rest_framework/crispy_form.html' when crispy forms are installed) but does NOT ship the form.html file anywhere. Instead it has a fallback to a static form in it's own backend.py file.

try:
    template = loader.get_template(self.template)
except TemplateDoesNotExist:
    template = Template(template_default)'

You should do the same and import template_default from django_filters.rest_framework

Regards, Alex

[rpkilby]

Hi @one4many - thanks for reporting. The backend code changed a little when migrating it from DRF to django-filter.rest_framework. I forgot to make the corresponding changes to the backend here.

For now, you should be able to safely set the Backend.template to 'rest_framework/filters/django_filter.html' or the crispy-forms alternative. DRF still ships these templates and will continue to do so until at least 3.6/3.7.

[george-silva]

having the same issue here. Where is that this code should be changed? in backend.py?

I hate monkey-patching 👎

[rpkilby]

You don't have to monkey patch - you can always inherit and change the path.

from rest_framework_filters import backends

class MyBackend(backends.DjangoFilterBackend):
    template = 'template/path.html'

[rpkilby]

This should be fixed on master.