require-dir-object

Turn a directory into a tree of objects with the required version of each file.

Example

Given a directory of JavaScript files:

.
├── fish.js
├── folder_with_index
│   ├── index.js
│   └── other_file.js
├── index.js
├── other_file.js
└── other_folder
    ├── badger.js
    └── badger_fish.js

index.js

module.exports = require("require-dir-object")(__dirname, {case: "camel"});

Would be equivalent to:

module.exports = {
    fish: require("./fish"),
    otherFile: require("./other_file"),
    otherFolder: {
        badger: require("./other_folder/badger"),
        badgerFish: require("./other_folder/badger_fish")
    },
    folderWithIndex: require("./folder_with_index")
};

Options

Name	Description	Type	Example	Default
case	Converts file naming method	string	{case: "camel"}	null
depth	Limit sub-directory search depth	int	{depth: 3}	Number.MAX_VALUE
exclude	Exclude files at a specific path	string or array	{exclude: "fish.js"}	[]
ext	Search for a specific extension	string	{ext: ".xml"}	".js"
func	Call a function on found file	function	{ext: fs.readFileSync}	require

Available case conversions are camel, snake, kebab, capitalize.

Notes

• Every folder is turned into a sub-object.
• If a folder has an index it will load that in favor of folder contents.

License

MIT