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Solution by Walther #8

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fda5e07
solution
wahez Dec 20, 2022
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wahez Dec 20, 2022
4eb4861
Read stdin
wahez Dec 21, 2022
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46 changes: 16 additions & 30 deletions README.md
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# Advent of Code 2022

Submit your challenge solutions here!

## Rules for participating

1. Assignments will be published online on a Sunday with entries/solutions due by Wednesday 18:00 local time
2. Entry in the form of a Pull Request to the Optiver Github repo Advent of Code 2022 - Amsterdam Contest.
3. The code has to accept puzzle input in some documented way.
4. The code has to work / be reproducible for the judges - documentation please.
5. The code has to complete within 5 minutes runtime.
6. The jury judges on the Thursday, winner will be announced on Friday - the winner will be announced via e-mail.
7. Jurors are not allowed to participate in the contest.


## Contest 1: Esolang

Solve the **Dec 04** challenge in the most esoteric language

## Contest 2: Obfuscation

Solve the **Dec 11** challenge in the most obscure way possible

Allowed languages: Python 3.9, C, C++

## Contest 3: Code golf

Solve the **Dec 18** challenge in the least amount of bytes possible

**Note**: has to compile / run with 'common available' compilers / runtimes on a "default" OS install of Ubuntu 22.10 or Windows 11.
My submission for short code for day 18. It uses 163 bytes.

Running:
cat <input_file> | python3 day18.py

Documentation:
l=[eval(f'[{s}]')for s in sys.stdin]
This reads strings (s) from the input file into a list of voxels (3D pixels) of lava(l).

print(sum(list(map(sum,zip(v,d)))not in l
for v in l
for d in[[0,0,1],[0,0,-1],[0,1,0],[0,-1,0],[1,0,0],[-1,0,0]]))
This part 'for v in l for d in[[0,0,1],[0,0,-1],[0,1,0],[0,-1,0],[1,0,0],[-1,0,0]]' loops through the voxels (v) of the lava (l) and through the 6 directions (d).
This part 'list(map(sum,zip(v,d)))' calculates the position of a neighbour given voxel (v) and direction(d).
This part '... not in l' then checks if that neighbour is in the lava (l). If this is not true it means we found a surface with lava on one side and air on the other.
This part 'print(sum(...))' sums those booleans and prints the count of surfaces we found.
5 changes: 5 additions & 0 deletions day18.py
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import sys
l=[eval(f'[{s}]')for s in sys.stdin]
print(sum(list(map(sum,zip(v,d)))not in l
for v in l
for d in[[0,0,1],[0,0,-1],[0,1,0],[0,-1,0],[1,0,0],[-1,0,0]]))