"constructor" property of function prototype objects does not show up in autocomplete suggestions

[todor2810]

• Version: v7.10.0
• Platform: Linux x1 4.4.0-93-generic test-require-resolve: use case insensitive compare #116-Ubuntu SMP Fri Aug 11 21:17:51 UTC 2017 x86_64 x86_64 x86_64 GNU/Linux

Example:

> function f() {}
> f.prototype.
f.prototype.__defineGetter__      f.prototype.__defineSetter__      f.prototype.__lookupGetter__
f.prototype.__lookupSetter__      f.prototype.__proto__             f.prototype.constructor
f.prototype.hasOwnProperty        f.prototype.isPrototypeOf         f.prototype.propertyIsEnumerable
f.prototype.toLocaleString        f.prototype.toString              f.prototype.valueOf

> Object.getOwnPropertyNames(f.prototype);
[ 'constructor' ]

In the example above it only shows the inherited "constructor" property from Object.prototype.

Non-enumerable properties of other objects show up, though.
Example:

> let o = {};
> Object.defineProperty(o, "firstName", {value: "ted"});
> o.
o.__defineGetter__      o.__defineSetter__      o.__lookupGetter__      o.__lookupSetter__
o.__proto__             o.constructor           o.hasOwnProperty        o.isPrototypeOf
o.propertyIsEnumerable  o.toLocaleString        o.toString              o.valueOf

o.firstName

[TimothyGu]

The constructor property you are seeing is an own property of f.prototype that points to f itself.

[targos]

This is a more general issue. Take this example:

var x = Object.create(null);
x.a = 1;
x.b = 2;
var y = Object.create(x);
y.a = 3;
y.c = 4;

Completion for y.<tab><tab>:

> y.
y.a  y.b  

y.c  

I would also expect y.a to be next to y.c because the own property shadows the property on the prototype.

[todor2810]

@targos Should I close the issue then?

[targos]

@pretodor Not at all. I think it's a valid issue.