Is it possible to deserialize a custom class from MessagePackObject

[leonidumanskiy]

Hi,
I know how to deserialize a custom class from a Stream:

var serializer = MessagePackSerializer.Get();
var value = serializer.Unpack(stream);

Is it possible to deserialize a class the same way directly from the MessagePackObject and not from the stream?

[yfakariya]

No, there are no Unpackers to support it. But it sounds good.

[leonidumanskiy]

I am asking because I have a basic "rpc-like" messaging system, and I want to serialize an object from one of the parameters. So it looks like this:
{
"command": "create_user",
"parameters": {
"hash": 1234,
"user": {"user_name": "test_user", "password": "1234", "email": "test@test.com"}
}
}

So I need to receive a command first, check what it is and than deserialize a User object from the second parameter. Is there any "right" way to to it?

[yfakariya]

Sorry I missed the additional question. I recommend you to implement following class:

public class Foo {
  public string Command { get; set; }
  public Dictionary<string, MessagePackObject> Parameters { get; set; }
}

and then, you check Parameters and use. I agree that it is not convinient at all, so I'll add ObjectUnpacker like API in future release.

[leonidumanskiy]

@yfakariya that's what I have right now.
And that's a problem I described in my first message - after taking MessagePackObject from the Parameters dictionary, I can't deserialize it into the class/object.
Instead, I have to write

var user = new User(Parameters["user_name"].AsString(), Parameters["password"].AsString(), Parameters["email"].AsString());

which is really annoying. Especially when my class has about 20 different properties :)
Hope to see an update asap!

[TSnake41]

Hi, I've found a solution if you know the type

MessagePackObject obj;
Type type;
object output;
using (MemoryStream stream = new MemoryStream())
{
     using (Packer packer = Packer.Create(stream))
     {
            obj.PackToMessage(packer, new PackingOptions());
            stream.Position = 0;
            output = SerializationContext.CreateClassicContext().GetSerializer(type).Unpack(stream);
      }
}

You got an object with the right type.

[yfakariya]

I will add helper extension methods in next release. It will be based on @TSnake41's idea. Thank you.

[yfakariya]

This was implemented in 0.9.