[Feature]: Distinct field values

[filip-halt]

Is there an existing issue for this?

• I have searched the existing issues

Is your feature request related to a problem? Please describe.

Find all the unique field values in a collection without having to iterate through all data.

Describe the solution you'd like.

Something equivalent to sql query(select distinct field_name from mytable)

Describe an alternate solution.

No response

Anything else? (Additional Context)

No response

[xiaofan-luan]

is there a specific use case for the distinct clause?

[xiaofan-luan]

is it in search or only in query?

[faileon]

Is there any plans for this? My use case would be to present user with a list of available values which can be used for filtering in future queries. Without this I have to manage a list of distinct values myself elsewhere.

[xiaofan-luan]

can you describe you data model and the specific use case so I can give more advice

[faileon]

Let me try. I let my users store their arbitrary documents in Milvus. I let them define which fields should be used to make embeddings and which are metadata. For each tenant I create a different collection. Users define from which fields on the original documents I should make embeddings and which to use as metadata for filtering purposes. Let's say one of my users has collection of "articles" and defined "category" as a metadata field that can be of any string value ("sport", "news",...). I would like to get distinct values of said "category" field - is that possible within Milvus?

[cardoso-neto]

I also couldn't find how to do this.

[xiaofan-luan]

I thought groupby feature is what you are looking for.
You can groupby a field name and get top k most related group but not entity.
is that what you are looking for? @cardoso-neto
This feature will be released on 2.4

[cardoso-neto]

This would work indeed. Looking forward.

[cardoso-neto]

My use case is reading all unique values of a Milvus collection column. More specifically the column I use for partition key. Since Milvus "maps" that to a standardized name (_default_i), I couldn't use Collection().partitions for that.

[xiaofan-luan]

_default_i

So that's saying you want to know how many partition keys are there in total?

[xiaofan-luan]

which means count the distinct partitionkey

[xiaofan-luan]

/assign @jaime0815
sounds like something we need to work on