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Lookup time #21

@th0ma5w

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@th0ma5w

I am probably saying the same thing as other just I don't have the proper terms probably but to save on lookup time:

Take the binary representation of every transformation and sum them, and that becomes the object hash.

When evaluating a new object do the same and that hash should match any rotation with just one match lookup?

Probably a way to make a tree of these as well but I imagine the hashing is effectively doing that anyway.

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