Add quick fix for `This condition will always return true since the function is always defined. Did you mean to call it instead`

[mjbvz]

TypeScript Version: 3.7.0-dev.20191003

Search Terms:

• quick fix
• code action
• function
• missing call

Code

const val = {
    isTrue() { return true; }
}

if (val.isTrue) {
    console.log(true);
}

This code produces the error: This condition will always return true since the function is always defined. Did you mean to call it instead? for the conditional

Expected behavior:
A quick fix to add the missing call is returned. This would change the code to:

const val = {
    isTrue() { return true; }
}

if (val.isTrue()) {
    console.log(true);
}

Actual behavior:
No quick fixes