Destructuring array polyfill isn't equivalent to new JS

[Validark]

Same deal as #31469

Search Terms: Destructuring array Polyfill concat

Code

const k = [1, 2];
const o = [3, ...k, k[0]++];
console.log(o.join(", "));

Compiles to

var k = [1, 2];
var o = [3].concat(k, [k[0]++]);
console.log(o.join(", "));

Or, on latest:

"use strict";
var __spreadArrays = (this && this.__spreadArrays) || function () {
    for (var s = 0, i = 0, il = arguments.length; i < il; i++) s += arguments[i].length;
    for (var r = Array(s), k = 0, i = 0; i < il; i++)
        for (var a = arguments[i], j = 0, jl = a.length; j < jl; j++, k++)
            r[k] = a[j];
    return r;
};
Object.defineProperty(exports, "__esModule", { value: true });
var k = [1, 2];
var o = __spreadArrays([3], k, [k[0]++]);
console.log(o.join(", "));

Expected behavior: 3, 1, 2, 1

Actual behavior: 3, 2, 2, 1

Playground Link: https://www.typescriptlang.org/play/index.html?target=1#code/MYewdgzgLgBA1jAvDA2gRgDQwEwF0DcAUKJLCEqgMxYB0dcWcKADLgNRsHHgQgA2AUxp8QAcwAUIGgCsQASzDiARFiUBKNfiA

Related Issues: #31469

The solution is the same as #32514. You can only concat/__spreadArrays one array at a time.

Also applies to call stacks:

let arr = [0];
console.log(...arr, arr[0]++);

Expected: 0, 0
Got: 1, 0