Closed
Description
TypeScript Version: 3.4.0-dev.20190201
Search Terms:
Extracting string from key breaks inference;
Extract<keyof T, string>
breaks inference;
Extract<keyof T, string>
breaks inference for deep keys;
Code
interface DeepObject {
[k1: string]: {
[k2: string]: any
};
}
type keys2broken<O extends DeepObject, K1 extends keyof O> =
O[K1] extends object ? Extract<keyof O[K1], string> : never;
type keys2working<O extends DeepObject, K1 extends keyof O> =
O[K1] extends object ? keyof O[K1] : never;
type keys2workaround<O extends DeepObject, K1 extends keyof O> =
Extract<O[K1] extends object ? keyof O[K1] : never, string>;
interface Foo extends DeepObject {
"a": {
"1": 123;
"2": string;
"3": boolean;
};
}
class Bar<O extends DeepObject>{
broken<
K1 extends keyof O,
K2 extends keys2broken<O, K1>,
V extends O[K1][K2]
>(k1: K1, k2: K2, value: V) {
}
working<
K1 extends keyof O,
K2 extends keys2working<O, K1>,
V extends O[K1][K2]
>(k1: K1, k2: K2, value: V) {
}
workaround<
K1 extends keyof O,
K2 extends keys2workaround<O, K1>,
V extends O[K1][K2]
>(k1: K1, k2: K2, value: V) {
}
}
const bar = new Bar<Foo>();
bar.broken("a", "1", true); // broken - 2nd argument is of type "1" | "2" | "3".
bar.working("a", "1", true); // ok - true is not allowed
bar.workaround("a", "1", true); // ok - true is not allowed
Expected behavior:
bar.broken("a", "1", true);
should infer type "1"
.
Actual behavior:
bar.broken("a", "1", true);
infers type "1" | "2" | "3"
.
Playground Link:
some smart text, a.k.a. bad sense of humour
Related issues:
#25065