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overloads.js
line: 79
for (const t of ['type', 'null', 'bool', 'string', 'int', 'double']) {
binaryOverload(t, '==', t, (a, b) => a === b)
}
I think it's better like this, to keep comparision of number and bigint
for (const t of ['type', 'null', 'bool', 'string', 'int', 'double']) {
binaryOverload(t, '==', t, (a, b) => isEqual(a, b))
}
lazharichir
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