expose $.grep() as an interface to Array.filter

jasondscott · Oct 3, 2012 · e92afc9 · e92afc9
1 parent ee9cda0
commit e92afc9
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diff --git a/src/zepto.js b/src/zepto.js
@@ -275,6 +275,10 @@ var Zepto = (function() {
     return elements
   }
 
+  $.grep = function(elements, callback){
+    return filter.call(elements, callback)
+  }
+
   if (window.JSON) $.parseJSON = JSON.parse
 
   // Define methods that will be available on all

diff --git a/test/zepto.html b/test/zepto.html
@@ -724,6 +724,12 @@ <h1>Zepto DOM unit tests</h1>
         t.assertEqual('name=banana,taste=sweet', results.sort().join(','))
       },
 
+      testDollarGrep: function(t){
+        var fruits = ['apples', 'oranges', 'pineapple', 'peach']
+        var result = $.grep(fruits, function(name){ return /apple/.test(name) })
+        t.assertEqualCollection(['apples', 'pineapple'], result)
+      },
+
       testDollarEach: function(t){
         var array = ['a','b','c'], object = { a: 1, b: 2, c: 3 }, result