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🙋♂ Question
const a = { id: 1 };
const b = { id: 2, children: [a] };
const objs = { 1: a, 2: b };
const fn = produce((draft) => {
draft[2].children[0].x = 1;
});
const r = fn(objs);
console.log(r[1]); // {id:1}
console.log(r[2].children[0]); //{id:1, x:1}
In two places of objs
we have two pointers to the same object a
but when we change it in one place we treat it like two different objects.
I expected that to be
console.log(r[1]); // {id:1, x:1}
console.log(r[2].children[0]); //{id:1, x:1}
I didn't find anything about that in docs.