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fix: use V(graph) as we should #1433

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fix: use V(graph) as we should #1433

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maelle
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@maelle maelle commented Jul 17, 2024

@maelle maelle requested a review from szhorvat July 17, 2024 12:14
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@@ -520,7 +520,7 @@ vertex.attributes <- function(graph, index = V(graph)) {

if (!missing(index)) {
index_is_natural_sequence <- (length(index) == vcount(graph) &&
identical(index, seq(1, vcount(graph))))
identical(index, V(graph)))
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I still think this should be

Suggested change
identical(index, V(graph)))
identical(index, as.numeric(seq_len(vcount(graph)))))

We want to cater for cases where !missing(index) but index is still essentially V(g) . I see:

library(igraph)
g <- make_ring(10)

identical(V(g), V(g))
#> [1] FALSE

Created on 2024-07-18 with reprex v2.1.0

Similarly to #1432 (comment).

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graph <- make_ring(5)
index <- V(graph)
identical(index, as.numeric(seq_len(vcount(graph))))
# returns FALSE.

Try all(index == V(graph))

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@clpippel: all() is challenging if the vectors are of different length? We'd still want to check the lengths first.

Would the all() route be faster?

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Perhaps we also want to check isTRUE(attr(g, "is_all")) ?

options(conflicts.policy = list(warn = FALSE))

library(igraph)
g <- make_ring(10)
dput(V(g))
#> structure(1:10, class = "igraph.vs", is_all = TRUE, env = <weak reference>, graph = "516d6a01-f041-48ae-bbe3-60dd751a8f4b")

Created on 2024-08-22 with reprex v2.1.0

Need to check if this other code path is ever touched -- easiest way by breaking it and running tests or revdeps.

@krlmlr
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krlmlr commented Apr 10, 2025

Continuing in #1427.

@krlmlr krlmlr closed this Apr 10, 2025
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V(g) not the same as 1:vcount Use as.numeric(seq_len(n)) in favor of seq(1, n)
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