Add support for llama4_text

[xenova]

New models:

• https://huggingface.co/onnx-community/MobileLLM-R1-140M-ONNX
• https://huggingface.co/onnx-community/MobileLLM-R1-360M-ONNX
• https://huggingface.co/onnx-community/MobileLLM-R1-950M-ONNX

Example usage:

import { pipeline, TextStreamer } from "@huggingface/transformers";

// Create a text generation pipeline
const generator = await pipeline(
  "text-generation",
  "onnx-community/MobileLLM-R1-140M-ONNX",
  { dtype: "fp32" },
);

// Define the list of messages
const messages = [
  { role: "user", content: "Solve x^2 - x - 6 = 0." },
];

// Generate a response
const output = await generator(messages, {
  max_new_tokens: 4096,
  do_sample: false,
  streamer: new TextStreamer(generator.tokenizer, {
    skip_prompt: true,
    skip_special_tokens: true,
  }),
});
console.log(output[0].generated_text.at(-1).content);

See example output

<think>
Okay, so I need to solve the quadratic equation x squared minus x minus 6 equals zero. Let me think about how to approach this. Hmm, quadratic equations can be solved using the quadratic formula, right? The standard form is ax² + bx + c = 0, so here it's x² - x - 6 = 0. 

First, I remember that to solve a quadratic equation, I need to find the roots. The quadratic formula is x = [-b ± √(b² - 4ac)] / (2a). In this case, a is 1, b is -1, and c is -6. Let me plug those values into the formula.

So, plugging in the values: x = [-(-1) ± √((-1)² - 4*1*(-6))]/(2*1). Let me compute the discriminant first. The discriminant is b² - 4ac. Plugging in the numbers: (-1)² is 1, and 4ac is 4*1*(-6) which is -24. So the discriminant is 1 - (-24) = 1 + 24 = 25. 

Now, the square root of 25 is 5. So the square root part is 5. Then, the numerator becomes -(-1) is 1, and the denominator is 2. So putting it all together, the solutions are [1 ± 5]/2. 

Calculating the two possibilities: 1 + 5 is 6, divided by 2 is 3. And 1 - 5 is -4, divided by 2 is -2. So the solutions are 3 and -2. 

Wait, let me check if I did everything correctly. The quadratic formula is x = [-b ± √(b² - 4ac)]/(2a). So in this case, a is 1, b is -1, c is -6. So plugging in: -(-1) is 1, and 4ac is 4*1*(-6) = -24. So discriminant is 1 - (-24) = 1 +24=25. Square root of 25 is 5. So yes, the roots are [1 ±5]/2. So 1+5 is 6, divided by 2 is 3, and 1-5 is -4 divided by 2 is -2. That seems right. 

I don't think I made any mistakes here. Let me verify by plugging in a value. Let's take x=3. Then the equation is 3² -3 -6 = 9 -3 -6 = 0. Yep, that works. What about x=-2? (-2)^2 - (-2) -6 = 4 +2 -6 = 0. Also works. So the solutions are 3 and -2. 

I think that's all. The quadratic formula gives the roots, and plugging in the values checks out. So the answer should be 3 and -2.
</think>To solve the quadratic equation \(x^2 - x - 6 = 0\), we use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = 1\), \(b = -1\), and \(c = -6\).

First, we calculate the discriminant:
\[
b^2 - 4ac = (-1)^2 - 4(1)(-6) = 1 + 24 = 25
\]
The square root of the discriminant is:
\[
\sqrt{25} = 5
\]

Next, we substitute \(a\), \(b\), and \(c\) into the quadratic formula:
\[
x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4(1)(-6)}}{2(1)} = \frac{1 \pm \sqrt{1 + 24}}{2} = \frac{1 \pm \sqrt{25}}{2} = \frac{1 \pm 5}{2}
\]

This gives us two solutions:
\[
x = \frac{1 + 5}{2} = \frac{6}{2} = 3
\]
\[
x = \frac{1 - 5}{2} = \frac{-4}{2} = -2
\]

Thus, the solutions to the equation \(x^2 - x - 6 = 0\) are:
\[
\boxed{3} \quad \text{and} \quad \boxed{-2}
\]

[HuggingFaceDocBuilderDev]

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