Is there a way to synthesize a spectrum for specific x axis values?

[nicocopez]

I want to synthesize a spectrum which has a given x-axis range. Normally, if I get the x-axis vector of a spectrum, the space between the x-axis points are not equal. Is there a straight forward way to do so within ramanchada2?

I see there is the xcal option, but could I used it to load a given x-axis vector?

Thank you in advance for your time!

[georgievgeorgi]

Yes, here is the example:

import numpy as np
import ramanchada2 as rc2

xarr = np.array([1, 1.1, 2, 2.2, 3, 3.3, 4, 4.4, 5, 5.5])
yarr = np.random.exponential(size=len(xarr))
rc2.spectrum.Spectrum(x=xarr, y=yarr).plot(fmt=':.')

[nicocopez]

Ok, this is great! So if I got it right, I can create my spectrum with numpy functions and then convert it to the class Spectrum, correct? Thank you Georgi!

[georgievgeorgi]

rc2.spectrum.Spectrum(x, y, metadata) expects x and y to be of type numpy array and returns a spectrum with these axes.
At the moment there is no strict check whether

len(x) == len(y)

So the user should take care of that.
also note that in the resulting Spectrum x-axis will be sorted in ascending order so the following example will produce a straight line:

xarr = np.array([10, 5, 1, 20])
rc2.spectrum.Spectrum(x=xarr, y=xarr).plot(fmt=':.')