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Improve yaml log escaping #4080

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logging: improve escaping in yaml output
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joennlae committed Nov 14, 2023
commit 6ee4682271b65f46b7df8cfc72058d856fadc7d1
1 change: 1 addition & 0 deletions common/common.cpp
Original file line number Diff line number Diff line change
Expand Up @@ -1188,6 +1188,7 @@ void dump_string_yaml_multiline(FILE * stream, const char * prop_name, const cha
if (!data_str.empty() && (std::isspace(data_str[0]) || std::isspace(data_str.back()))) {
data_str = std::regex_replace(data_str, std::regex("\n"), "\\n");
data_str = std::regex_replace(data_str, std::regex("\""), "\\\"");
data_str = std::regex_replace(data_str, std::regex("\\\\[^n\"]"), "\\$&");
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I think raw string literals would be clearer here. And I think it should be ordered like this so a \n in the input is correctly escaped as \\n (correct me if I'm wrong):

Suggested change
data_str = std::regex_replace(data_str, std::regex("\n"), "\\n");
data_str = std::regex_replace(data_str, std::regex("\""), "\\\"");
data_str = std::regex_replace(data_str, std::regex("\\\\[^n\"]"), "\\$&");
data_str = std::regex_replace(data_str, std::regex(R"(\\)"), R"(\\)");
data_str = std::regex_replace(data_str, std::regex(R"(\n)"), R"(\n)");
data_str = std::regex_replace(data_str, std::regex(R"(")"), R"(\")");

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Thank you for the feedback :-)

I see your suggestion regarding the raw string :-) I agree it makes it less confusing, but on the other side, there is also some mind gymnastics involved in understanding why we need to do the:

data_str = std::regex_replace(data_str, std::regex(R"(\n)"), R"(\n)");

replacing the same? (I mean, it is because the regex string needs the escaping for that matching, but is that obvious for the casual code reader 😄 )

I included your proposal to use raw strings, and thank you for the feedback.

data_str = "\"" + data_str + "\"";
fprintf(stream, "%s: %s\n", prop_name, data_str.c_str());
return;
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