RSS XML Link Substitution - Python Api

background: d.cosx.org - 将 RSS 源中的相对链接转化为绝对链接

Try online app

• https://rssxml-linksub.herokuapp.com

Simple case（python Requests client for example）

# GET
from os.path import join
import requests

resp = requests.get(
    "https://rssxml-linksub.herokuapp.com/api/?"
    "rss=https://rssxml-linksub.herokuapp.com/static/demo.xml"
)
assert resp.status_code == 200
assert resp.headers["Content-Type"] == "text/xml; charset=utf-8"
print(resp.text)

# POST
from os.path import join
from lxml import etree
import requests

tree = etree.parse(join("static", "demo.xml"))
root = tree.getroot()
resp = requests.post(
    "http://127.0.0.1:8000/api/",
    headers={"Content-Type": "application/xml"},
    data=etree.tostring(root, encoding='utf-8')
)
assert resp.status_code == 200
assert resp.headers["Content-Type"] == "text/xml; charset=utf-8"
print(resp.text)

Dependencies

• Python-3.7.9
• requirements.txt

More about xml parser choosen: At very beginning, I choose defusedxml.ElementTree (a wrapper over xml.etree.ElementTree for more security), but it always loss xml declaration when using xml.etree.ElementTree.tostring() to export. According to documents, xml.etree.ElementTree.tostring(..., xml_declaration=xxx) only valid after python >= 3.8. Bitterly, platform like Heroku, vercel.com offer defaut python runtime < 3.8. So finally choose lxml.

Deployment

• Heroku - getting-started-with-python
  • runtime.txt
  • Procfile