Add Solution and Readme.md for 30[Java] #62
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yanglbme
reviewed
Oct 26, 2018
| words = ["word","good","good"] | ||
| (ps:原题的例子为 words = ["word","student"] 和题目描述不符，这里私自改了一下) | ||
| 输出: [] | ||
| ``` |
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😁一点小建议噢，代码块的添加与 LeetCode 保持一致：示例字体加粗，输入输出用代码块包围。
e.g.
示例 1:
输入:
s = "barfoothefoobarman",
words = ["foo","bar"]
输出: [0,9]
解释: 从索引 0 和 9 开始的子串分别是 "barfoor" 和 "foobar" 。
输出的顺序不重要, [9,0] 也是有效答案。
示例 2:
输入:
s = "wordgoodstudentgoodword",
words = ["word","student"]
输出: []
| if(s.length() == 0 || words[0].length() == 0 || s.length() < words.length * words[0].length()) { | ||
| return re; | ||
| } | ||
| // 用< 单词，出现次数 > 来存储 words 中的元素，方便查找 |
| if(map.containsKey(tempStr)) { | ||
| HashMap<String,Integer> searched = new HashMap<>(); | ||
| // 从后向前依次对比 | ||
| int tempIndex = j + lastStart; |
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这里缩进得有点多噢~是不是贴过来的时候乱了(⊙o⊙)？
后面代码注释也有缩进的问题。
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Correct my error in Readme.md for 029, and Add Solution and Readme.md for 30[Java]