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all_equalall_uniquebifurcatebifurcate_bychunkcompactcount_bycount_occurencesdeep_flattendifferencedifference_byeveryevery_nthfilter_non_uniquegroup_byhas_duplicatesheadinitialinitialize_2d_listinitialize_list_with_rangeinitialize_list_with_valuesintersectionintersection_bylastlongest_itemmax_nmin_nnoneoffsetsampleshufflesimilaritysomespreadsymmetric_differencesymmetric_difference_bytailunionunion_byunique_elementszip
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Check if all elements in a list are equal.
Use [1:] and [:-1] to compare all the values in the given list.
def all_equal(lst):
return lst[1:] == lst[:-1]Examples
all_equal([1, 2, 3, 4, 5, 6]) # False
all_equal([1, 1, 1, 1]) # TrueReturns True if all the values in a flat list are unique, False otherwise.
Use set() on the given list to remove duplicates, compare its length with the length of the list.
def all_unique(lst):
return len(lst) == len(set(lst))Examples
x = [1,2,3,4,5,6]
y = [1,2,2,3,4,5]
all_unique(x) # True
all_unique(y) # FalseSplits values into two groups.
If an element in filter is True, the corresponding element in the collection belongs to the first group; otherwise, it belongs to the second group.
Use list comprehension and enumerate() to add elements to groups, based on filter.
def bifurcate(lst, filter):
return [
[x for i,x in enumerate(lst) if filter[i] == True],
[x for i,x in enumerate(lst) if filter[i] == False]
]Examples
bifurcate(['beep', 'boop', 'foo', 'bar'], [True, True, False, True]) # [ ['beep', 'boop', 'bar'], ['foo'] ]Splits values into two groups according to a function, which specifies which group an element in the input list belongs to.
If the function returns True, the element belongs to the first group; otherwise, it belongs to the second group.
Use list comprehension to add elements to groups, based on fn.
def bifurcate_by(lst, fn):
return [
[x for x in lst if fn(x)],
[x for x in lst if not fn(x)]
]Examples
bifurcate_by(['beep', 'boop', 'foo', 'bar'], lambda x: x[0] == 'b') # [ ['beep', 'boop', 'bar'], ['foo'] ]Chunks a list into smaller lists of a specified size.
Use list() and range() to create a list of the desired size.
Use map() on the list and fill it with splices of the given list.
Finally, return use created list.
from math import ceil
def chunk(lst, size):
return list(
map(lambda x: lst[x * size:x * size + size],
list(range(0, ceil(len(lst) / size)))))Examples
chunk([1,2,3,4,5],2) # [[1,2],[3,4],5]Removes falsey values from a list.
Use filter() to filter out falsey values (False, None, 0, and "").
def compact(lst):
return list(filter(bool, lst))Examples
compact([0, 1, False, 2, '', 3, 'a', 's', 34]) # [ 1, 2, 3, 'a', 's', 34 ]Groups the elements of a list based on the given function and returns the count of elements in each group.
Use map() to map the values of the given list using the given function.
Iterate over the map and increase the element count each time it occurs.
def count_by(arr, fn=lambda x: x):
key = {}
for el in map(fn, arr):
key[el] = 0 if el not in key else key[el]
key[el] += 1
return keyExamples
from math import floor
count_by([6.1, 4.2, 6.3], floor) # {4: 1, 6: 2}
count_by(['one', 'two', 'three'], len) # {3: 2, 5: 1}Counts the occurrences of a value in a list.
Increment a counter for every item in the list that has the given value and is of the same type.
def count_occurrences(lst, val):
return len([x for x in lst if x == val and type(x) == type(val)])Examples
count_occurrences([1, 1, 2, 1, 2, 3], 1) # 3Deep flattens a list.
Use recursion.
Define a function, spread, that uses either list.extend() or list.append() on each element in a list to flatten it.
Use list.extend() with an empty list and the spread function to flatten a list.
Recursively flatten each element that is a list.
def spread(arg):
ret = []
for i in arg:
if isinstance(i, list):
ret.extend(i)
else:
ret.append(i)
return ret
def deep_flatten(lst):
result = []
result.extend(
spread(list(map(lambda x: deep_flatten(x) if type(x) == list else x, lst))))
return resultExamples
deep_flatten([1, [2], [[3], 4], 5]) # [1,2,3,4,5]Returns the difference between two iterables.
Create a set from b, then use list comprehension on a to only keep values not contained in the previously created set, _b.
def difference(a, b):
_b = set(b)
return [item for item in a if item not in _b]Examples
difference([1, 2, 3], [1, 2, 4]) # [3]Returns the difference between two lists, after applying the provided function to each list element of both.
Create a set by applying fn to each element in b, then use list comprehension in combination with fn on a to only keep values not contained in the previously created set, _b.
def difference_by(a, b, fn):
_b = set(map(fn, b))
return [item for item in a if fn(item) not in _b]Examples
from math import floor
difference_by([2.1, 1.2], [2.3, 3.4],floor) # [1.2]
difference_by([{ 'x': 2 }, { 'x': 1 }], [{ 'x': 1 }], lambda v : v['x']) # [ { x: 2 } ]Returns True if the provided function returns True for every element in the list, False otherwise.
Iterate over the elements of the list to test if every element in the list returns True based on fn.
Omit the seconds argument, fn, to check if all elements are True.
def every(lst, fn=lambda x: not not x):
for el in lst:
if not fn(el):
return False
return TrueExamples
every([4, 2, 3], lambda x: x > 1) # True
every([1, 2, 3]) # TrueReturns every nth element in a list.
Use [nth-1::nth] to create a new list that contains every nth element of the given list.
def every_nth(lst, nth):
return lst[nth-1::nth]Examples
every_nth([1, 2, 3, 4, 5, 6], 2) # [ 2, 4, 6 ]Filters out the non-unique values in a list.
Use list comprehension and list.count() to create a list containing only the unique values.
def filter_non_unique(lst):
return [item for item in lst if lst.count(item) == 1]Examples
filter_non_unique([1, 2, 2, 3, 4, 4, 5]) # [1, 3, 5]Groups the elements of a list based on the given function.
Use list() in combination with map() and fn to map the values of the list to the keys of an object.
Use list comprehension to map each element to the appropriate key.
def group_by(lst, fn):
groups = {}
for key in list(map(fn,lst)):
groups[key] = [item for item in lst if fn(item) == key]
return groupsExamples
import math
group_by([6.1, 4.2, 6.3], math.floor); # {4: [4.2], 6: [6.1, 6.3]}
group_by(['one', 'two', 'three'], 'length'); # {3: ['one', 'two'], 5: ['three']}Returns True if there are duplicate values in a flast list, False otherwise.
Use set() on the given list to remove duplicates, compare its length with the length of the list.
def has_duplicates(lst):
return len(lst) != len(set(lst))Examples
x = [1,2,3,4,5,5]
y = [1,2,3,4,5]
has_duplicates(x) # True
has_duplicates(y) # FalseReturns the head of a list.
use lst[0] to return the first element of the passed list.
def head(lst):
return lst[0]Examples
head([1, 2, 3]); # 1Returns all the elements of a list except the last one.
Use lst[0:-1] to return all but the last element of the list.
def initial(lst):
return lst[0:-1]Examples
initial([1, 2, 3]); # [1,2]Initializes a 2D list of given width and height and value.
Use list comprehension and range() to generate h rows where each is a list with length h, initialized with val.
If val is not provided, default to None.
Explain briefly how the snippet works.
def initialize_2d_list(w,h, val = None):
return [[val for x in range(w)] for y in range(h)]Examples
initialize_2d_list(2, 2, 0) # [[0,0], [0,0]]Initializes a list containing the numbers in the specified range where start and end are inclusive with their common difference step.
Use list and range() to generate a list of the appropriate length, filled with the desired values in the given range.
Omit start to use the default value of 0.
Omit step to use the default value of 1.
def initialize_list_with_range(end, start = 0, step = 1):
return list(range(start, end + 1, step))Examples
initialize_list_with_range(5) # [0, 1, 2, 3, 4, 5]
initialize_list_with_range(7,3) # [3, 4, 5, 6, 7]
initialize_list_with_range(9,0,2) # [0, 2, 4, 6, 8]Initializes and fills a list with the specified value.
Use list comprehension and range() to generate a list of length equal to n, filled with the desired values.
Omit val to use the default value of 0.
def initialize_list_with_values(n, val = 0):
return [val for x in range(n)]Examples
initialize_list_with_values(5, 2) # [2, 2, 2, 2, 2]Returns a list of elements that exist in both lists.
Create a set from b, then use list comprehension on a to only keep values contained in both lists.
def intersection(a, b):
_b = set(b)
return [item for item in a if item in _b]Examples
intersection([1, 2, 3], [4, 3, 2]) # [2, 3]Returns a list of elements that exist in both lists, after applying the provided function to each list element of both.
Create a set by applying fn to each element in b, then use list comprehension in combination with fn on a to only keep values contained in both lists.
def intersection_by(a, b, fn):
_b = set(map(fn, b))
return [item for item in a if fn(item) in _b]Examples
from math import floor
intersection_by([2.1, 1.2], [2.3, 3.4],floor) # [2.1]Returns the last element in a list.
use lst[-1] to return the last element of the passed list.
def last(lst):
return lst[-1]Examples
last([1, 2, 3]) # 3Takes any number of iterable objects or objects with a length property and returns the longest one. If multiple objects have the same length, the first one will be returned.
Use max() with len as the key to return the item with the greatest length.
def longest_item(*args):
return max(args, key = len)Examples
longest_item('this', 'is', 'a', 'testcase') # 'testcase'
longest_item([1, 2, 3], [1, 2], [1, 2, 3, 4, 5]) # [1, 2, 3, 4, 5]
longest_item([1, 2, 3], 'foobar') # 'foobar'Returns the n maximum elements from the provided list.
If n is greater than or equal to the provided list's length, then return the original list (sorted in descending order).
Use sorted() to sort the list, [:n] to get the specified number of elements.
Omit the second argument, n, to get a one-element list.
def max_n(lst, n=1):
return sorted(lst, reverse=True)[:n]Examples
max_n([1, 2, 3]) # [3]
max_n([1, 2, 3], 2) # [3,2]Returns the n minimum elements from the provided list.
If n is greater than or equal to the provided list's length, then return the original list (sorted in ascending order).
Use sorted() to sort the list, [:n]to get the specified number of elements. Omit the second argument,n`, to get a one-element list.
def min_n(lst, n=1):
return sorted(lst, reverse=False)[:n]Examples
min_n([1, 2, 3]) # [1]
min_n([1, 2, 3], 2) # [1,2]Returns False if the provided function returns True for at least one element in the list, True otherwise.
Iterate over the elements of the list to test if every element in the list returns False based on fn.
Omit the seconds argument, fn, to check if all elements are False.
def none(lst, fn=lambda x: not not x):
for el in lst:
if fn(el):
return False
return TrueExamples
none([0, 1, 2, 0], lambda x: x >= 2 ) # False
none([0, 0, 0]) # TrueMoves the specified amount of elements to the end of the list.
Use lst[offset:] and lst[:offset] to get the two slices of the list and combine them before returning.
Explain briefly how the snippet works.
def offset(lst, offset):
return lst[offset:] + lst[:offset]Examples
offset([1, 2, 3, 4, 5], 2) # [3, 4, 5, 1, 2]
offset([1, 2, 3, 4, 5], -2) # [4, 5, 1, 2, 3]Returns a random element from an array.
Use randint() to generate a random number that corresponds to an index in the list, return the element at that index.
from random import randint
def sample(lst):
return lst[randint(0, len(lst) - 1)]Examples
sample([3, 7, 9, 11]) # 9Randomizes the order of the values of an list, returning a new list.
Uses the Fisher-Yates algorithm to reorder the elements of the list.
from copy import deepcopy
from random import randint
def shuffle(lst):
temp_lst = deepcopy(lst)
m = len(temp_lst)
while (m):
m -= 1
i = randint(0, m)
temp_lst[m], temp_lst[i] = temp_lst[i], temp_lst[m]
return temp_lstExamples
foo = [1,2,3]
shuffle(foo) # [2,3,1] , foo = [1,2,3]Returns a list of elements that exist in both lists.
Use list comprehension on a to only keep values contained in both lists.
def similarity(a, b):
return [item for item in a if item in b]Examples
similarity([1, 2, 3], [1, 2, 4]) # [1, 2]Returns True if the provided function returns True for at least one element in the list, False otherwise.
Iterate over the elements of the list to test if every element in the list returns True based on fn.
Omit the seconds argument, fn, to check if all elements are True.
def some(lst, fn=lambda x: not not x):
for el in lst:
if fn(el):
return True
return FalseExamples
some([0, 1, 2, 0], lambda x: x >= 2 ) # True
some([0, 0, 1, 0]) # TrueFlattens a list, by spreading its elements into a new list.
Loop over elements, use list.extend() if the element is a list, list.append() otherwise.
def spread(arg):
ret = []
for i in arg:
if isinstance(i, list):
ret.extend(i)
else:
ret.append(i)
return retExamples
spread([1,2,3,[4,5,6],[7],8,9]) # [1,2,3,4,5,6,7,8,9]Returns the symmetric difference between two iterables, without filtering out duplicate values.
Create a set from each list, then use list comprehension on each one to only keep values not contained in the previously created set of the other.
def symmetric_difference(a, b):
_a, _b = set(a), set(b)
return [item for item in a if item not in _b] + [item for item in b if item not in _a]Examples
symmetric_difference([1, 2, 3], [1, 2, 4]) # [3, 4]Returns the symmetric difference between two lists, after applying the provided function to each list element of both.
Create a set by applying fn to each element in every list, then use list comprehension in combination with fn on each one to only keep values not contained in the previously created set of the other.
def symmetric_difference_by(a, b, fn):
_a, _b = set(map(fn, a)), set(map(fn, b))
return [item for item in a if fn(item) not in _b] + [item for item in b if fn(item) not in _a]Examples
from math import floor
symmetric_difference_by([2.1, 1.2], [2.3, 3.4],floor) # [1.2, 3.4]Returns all elements in a list except for the first one.
Return lst[1:] if the list's length is more than 1, otherwise, return the whole list.
def tail(lst):
return lst[1:] if len(lst) > 1 else lstExamples
tail([1, 2, 3]); # [2,3]
tail([1]); # [1]Returns every element that exists in any of the two lists once.
Create a set with all values of a and b and convert to a list.
def union(a,b):
return list(set(a + b))Examples
union([1, 2, 3], [4, 3, 2]) # [1,2,3,4]Returns every element that exists in any of the two lists once, after applying the provided function to each element of both.
Create a set by applying fn to each element in a, then use list comprehension in combination with fn on b to only keep values not contained in the previously created set, _a.
Finally, create a set from the previous result and a and transform it into a list
def union_by(a,b,fn):
_a = set(map(fn, a))
return list(set(a + [item for item in b if fn(item) not in _a]))Examples
from math import floor
union_by([2.1], [1.2, 2.3], floor) # [2.1, 1.2]Returns the unique elements in a given list.
Create a set from the list to discard duplicated values, then return a list from it.
def unique_elements(li):
return list(set(li))Examples
unique_elements([1, 2, 2, 3, 4, 3]) # [1, 2, 3, 4]Creates a list of elements, grouped based on the position in the original lists.
Use max combined with list comprehension to get the length of the longest list in the arguments.
Loop for max_length times grouping elements.
If lengths of lists vary, use fill_value (defaults to None).
def zip(*args, fillvalue=None):
max_length = max([len(lst) for lst in args])
result = []
for i in range(max_length):
result.append([
args[k][i] if i < len(args[k]) else fillvalue for k in range(len(args))
])
return resultExamples
zip(['a', 'b'], [1, 2], [True, False]) # [['a', 1, True], ['b', 2, False]]
zip(['a'], [1, 2], [True, False]) # [['a', 1, True], [None, 2, False]]
zip(['a'], [1, 2], [True, False], fill_value = '_') # [['a', 1, True], ['_', 2, False]]Returns the average of two or more numbers.
Use sum() to sum all of the args provided, divide by len(args).
def average(*args):
return sum(args, 0.0) / len(args)Examples
average(*[1, 2, 3]) # 2.0
average(1, 2, 3) # 2.0Returns the average of a list, after mapping each element to a value using the provided function.
Use map() to map each element to the value returned by fn.
Use sum() to sum all of the mapped values, divide by len(lst).
def average_by(lst, fn=lambda x: x):
return sum(map(fn, lst), 0.0) / len(lst)Examples
average_by([{ 'n': 4 }, { 'n': 2 }, { 'n': 8 }, { 'n': 6 }], lambda x: x['n']) # 5.0Clamps num within the inclusive range specified by the boundary values a and b.
If num falls within the range, return num.
Otherwise, return the nearest number in the range.
def clamp_number(num,a,b):
return max(min(num, max(a,b)),min(a,b))Examples
clamp_number(2, 3, 5) # 3
clamp_number(1, -1, -5) # -1Converts a number to an array of digits.
Use map() combined with int on the string representation of n and return a list from the result.
def digitize(n):
return list(map(int, str(n)))Examples
digitize(123) # [1, 2, 3]Calculates the factorial of a number.
Use recursion.
If num is less than or equal to 1, return 1.
Otherwise, return the product of num and the factorial of num - 1.
Throws an exception if num is a negative or a floating point number.
def factorial(num):
if not ((num >= 0) & (num % 1 == 0)):
raise Exception(
f"Number( {num} ) can't be floating point or negative ")
return 1 if num == 0 else num * factorial(num - 1)Examples
factorial(6) # 720Generates an array, containing the Fibonacci sequence, up until the nth term.
Starting with 0 and 1, use list.apoend() to add the sum of the last two numbers of the list to the end of the list, until the length of the list reaches n. If nis less or equal to0, return a list containing 0`.
def fibonacci(n):
if n <= 0:
return [0]
sequence = [0, 1]
while len(sequence) <= n:
next_value = sequence[len(sequence) - 1] + sequence[len(sequence) - 2]
sequence.append(next_value)
return sequenceExamples
fibonacci(7) # [0, 1, 1, 2, 3, 5, 8, 13]Calculates the greatest common divisor of a list of numbers.
Use reduce() and math.gcd over the given list.
from functools import reduce
import math
def gcd(numbers):
return reduce(math.gcd, numbers)Examples
gcd([8,36,28]) # 4Checks if the given number falls within the given range.
Use arithmetic comparison to check if the given number is in the specified range.
If the second parameter, end, is not specified, the range is considered to be from 0 to start.
def in_range(n, start, end = 0):
if (start > end):
end, start = start, end
return start <= n <= endExamples
in_range(3, 2, 5); # True
in_range(3, 4); # True
in_range(2, 3, 5); # False
in_range(3, 2); # FalseChecks if the first numeric argument is divisible by the second one.
Use the modulo operator (%) to check if the remainder is equal to 0.
def is_divisible(dividend, divisor):
return dividend % divisor == 0Examples
is_divisible(6, 3) # TrueReturns True if the given number is even, False otherwise.
Checks whether a number is odd or even using the modulo (%) operator.
Returns True if the number is even, False if the number is odd.
def is_even(num):
return num % 2 == 0Examples
is_even(3) # FalseReturns True if the given number is odd, False otherwise.
Checks whether a number is even or odd using the modulo (%) operator.
Returns True if the number is odd, False if the number is even.
def is_odd(num):
return num % 2 != 0Examples
is_odd(3) # True
Returns the least common multiple of two or more numbers.
Define a function, spread, that uses either list.extend() or list.append() on each element in a list to flatten it.
Use math.gcd() and lcm(x,y) = x * y / gcd(x,y) to determine the least common multiple.
from functools import reduce
import math
def spread(arg):
ret = []
for i in arg:
if isinstance(i, list):
ret.extend(i)
else:
ret.append(i)
return ret
def lcm(*args):
numbers = []
numbers.extend(spread(list(args)))
def _lcm(x, y):
return int(x * y / math.gcd(x, y))
return reduce((lambda x, y: _lcm(x, y)), numbers)Examples
lcm(12, 7) # 84
lcm([1, 3, 4], 5) # 60Returns the maximum value of a list, after mapping each element to a value using the provided function.
Use map() with fn to map each element to a value using the provided function, convert to a list and use max() to return the maximum value.
def max_by(lst, fn):
return max(list(map(fn,lst)))Examples
max_by([{ 'n': 4 }, { 'n': 2 }, { 'n': 8 }, { 'n': 6 }], lambda v : v['n']) # 8Returns the minimum value of a list, after mapping each element to a value using the provided function.
Use map() with fn to map each element to a value using the provided function, convert to a list and use min() to return the minimum value.
def min_by(lst, fn):
return min(list(map(fn,lst)))Examples
min_by([{ 'n': 4 }, { 'n': 2 }, { 'n': 8 }, { 'n': 6 }], lambda v : v['n']) # 2Converts an angle from radians to degrees.
Use math.pi and the radian to degree formula to convert the angle from radians to degrees.
import math
def rads_to_degrees(rad):
return (rad * 180.0) / math.piExamples
import math
rads_to_degrees(math.pi / 2) # 90.0Returns the sum of a list, after mapping each element to a value using the provided function.
Use map() with fn to map each element to a value using the provided function, convert to a list and use sum() to return the sum of the values.
def sum_by(lst, fn):
return sum(list(map(fn,lst)))Examples
sum_by([{ 'n': 4 }, { 'n': 2 }, { 'n': 8 }, { 'n': 6 }], lambda v : v['n']) # 20Returns a flat list of all the keys in a flat dictionary.
Use dict.keys() to return the keys in the given dictionary.
Return a list() of the previous result.
def keys_only(flat_dict):
return list(flat_dict.keys())Examples
ages = {
"Peter": 10,
"Isabel": 11,
"Anna": 9,
}
keys_only(ages) # ['Peter', 'Isabel', 'Anna']Creates an object with the same keys as the provided object and values generated by running the provided function for each value.
Use dict.keys() to iterate over the object's keys, assigning the values produced by fn to each key of a new object.
def map_values(obj, fn):
ret = {}
for key in obj.keys():
ret[key] = fn(obj[key])
return retExamples
users = {
'fred': { 'user': 'fred', 'age': 40 },
'pebbles': { 'user': 'pebbles', 'age': 1 }
}
map_values(users, lambda u : u['age']) # {'fred': 40, 'pebbles': 1}Returns a flat list of all the values in a flat dictionary.
Use dict.values() to return the values in the given dictionary.
Return a list() of the previous result.
def values_only(dict):
return list(dict.values())Examples
ages = {
"Peter": 10,
"Isabel": 11,
"Anna": 9,
}
values_only(ages) # [10, 11, 9]Returns the length of a string in bytes.
Use string.encode('utf-8') to encode the given string and return its length.
def byte_size(string):
return len(string.encode('utf-8'))Examples
byte_size('😀') # 4
byte_size('Hello World') # 11Converts a string to camelcase.
Break the string into words and combine them capitalizing the first letter of each word, using a regexp, title() and lower.
import re
def camel(s):
s = re.sub(r"(\s|_|-)+", " ", s).title().replace(" ", "")
return s[0].lower() + s[1:]Examples
camel('some_database_field_name'); # 'someDatabaseFieldName'
camel('Some label that needs to be camelized'); # 'someLabelThatNeedsToBeCamelized'
camel('some-javascript-property'); # 'someJavascriptProperty'
camel('some-mixed_string with spaces_underscores-and-hyphens'); # 'someMixedStringWithSpacesUnderscoresAndHyphens'Capitalizes the first letter of a string.
Capitalize the first letter of the string and then add it with rest of the string.
Omit the lower_rest parameter to keep the rest of the string intact, or set it to True to convert to lowercase.
def capitalize(string, lower_rest=False):
return string[:1].upper() + (string[1:].lower() if lower_rest else string[1:])Examples
capitalize('fooBar') # 'FooBar'
capitalize('fooBar', True) # 'Foobar'Capitalizes the first letter of every word in a string.
Use string.title() to capitalize first letter of every word in the string.
def capitalize_every_word(string):
return string.title()Examples
capitalize_every_word('hello world!') # 'Hello World!'Decapitalizes the first letter of a string.
Decapitalize the first letter of the string and then add it with rest of the string.
Omit the upper_rest parameter to keep the rest of the string intact, or set it to True to convert to uppercase.
def decapitalize(string, upper_rest=False):
return str[:1].lower() + (str[1:].upper() if upper_rest else str[1:])Examples
decapitalize('FooBar') # 'fooBar'
decapitalize('FooBar', True) # 'fOOBAR'Checks if a string is an anagram of another string (case-insensitive, ignores spaces, punctuation and special characters).
Use str.replace() to remove spaces from both strings.
Compare the lengths of the two strings, return False if they are not equal.
Use sorted() on both strings and compare the results.
def is_anagram(str1, str2):
_str1, _str2 = str1.replace(" ", ""), str2.replace(" ", "")
if len(_str1) != len(_str2):
return False
else:
return sorted(_str1.lower()) == sorted(_str2.lower())Examples
is_anagram("anagram", "Nag a ram") # TrueChecks if a string is lower case.
Convert the given string to lower case, using str.lower() and compare it to the original.
def is_lower_case(string):
return string == string.lower()Examples
is_lower_case('abc') # True
is_lower_case('a3@$') # True
is_lower_case('Ab4') # FalseChecks if a string is upper case.
Convert the given string to upper case, using str.upper() and compare it to the original.
def is_upper_case(string):
return string == string.upper()Examples
is_upper_case('ABC') # True
is_upper_case('a3@$') # False
is_upper_case('aB4') # FalseConverts a string to kebab case.
Break the string into words and combine them adding - as a separator, using a regexp.
import re
def kebab(str):
return re.sub(r"(\s|_|-)+","-",
re.sub(r"[A-Z]{2,}(?=[A-Z][a-z]+[0-9]*|\b)|[A-Z]?[a-z]+[0-9]*|[A-Z]|[0-9]+",
lambda mo: mo.group(0).lower(),str)
)Examples
kebab('camelCase'); # 'camel-case'
kebab('some text'); # 'some-text'
kebab('some-mixed_string With spaces_underscores-and-hyphens'); # 'some-mixed-string-with-spaces-underscores-and-hyphens'
kebab('AllThe-small Things'); # "all-the-small-things"Returns True if the given string is a palindrome, False otherwise.
Use str.lower() and re.sub() to convert to lowercase and remove non-alphanumeric characters from the given string.
Then, compare the new string with its reverse.
from re import sub
def palindrome(string):
s = sub('[\W_]', '', string.lower())
return s == s[::-1]Examples
palindrome('taco cat') # TrueConverts a string to snake case.
Break the string into words and combine them adding _-_ as a separator, using a regexp.
import re
def snake(str):
return re.sub(r"(\s|_|-)+","-",
re.sub(r"[A-Z]{2,}(?=[A-Z][a-z]+[0-9]*|\b)|[A-Z]?[a-z]+[0-9]*|[A-Z]|[0-9]+",
lambda mo: mo.group(0).lower(),str)
)Examples
snake('camelCase'); # 'camel_case'
snake('some text'); # 'some_text'
snake('some-mixed_string With spaces_underscores-and-hyphens'); # 'some_mixed_string_with_spaces_underscores_and_hyphens'
snake('AllThe-small Things'); # "all_the_smal_things"Splits a multiline string into a list of lines.
Use str.split() and '\n' to match line breaks and create a list.
def split_lines(str):
return str.split('\n')Examples
split_lines('This\nis a\nmultiline\nstring.\n') # 'This\nis a\nmultiline\nstring.\n'Casts the provided value as an array if it's not one.
Use isinstance() to check if the given value is a list and return it as-is or encapsulated in a list accordingly.
def cast_list(val):
return val if isinstance(val, list) else [val]Examples
cast_list('foo'); # ['foo']
cast_list([1]); # [1] Angelos Chalaris |
 Stefan Feješ |
 Rohit Tanwar |
|---|
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