Key not found in dictionary on multiple booleans in where

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First of all, great job on this, I was actually doing it myself as well, but 
ended up getting extremely messy and did not get as far as you did, ended up 
scrapping it and using this.

Only issue I am having is the following query:

query.Where(x => (x.IsActive || x.IsLocked) && x.EmailAddress == 
"test@test.com");

Is giving the following error:

System.Collections.Generic.KeyNotFoundException : The given key was not present 
in the dictionary.

at System.Collections.Generic.Dictionary`2.get_Item(TKey key)
   at Resolver.LambdaResolver.BuildSql(MemberNode leftMember, MemberNode rightMember, ExpressionType op) in LambdaResolverTree.cs: line 80
   at System.Dynamic.UpdateDelegates.UpdateAndExecuteVoid4<T0,T1,T2,T3>(CallSite site, T0 arg0, T1 arg1, T2 arg2, T3 arg3)
   at Resolver.LambdaResolver.BuildSql(OperationNode node) in LambdaResolverTree.cs: line 46
   at System.Dynamic.UpdateDelegates.UpdateAndExecuteVoid2<T0,T1>(CallSite site, T0 arg0, T1 arg1)
   at Resolver.LambdaResolver.BuildSql(Node leftNode, Node rightNode, ExpressionType op) in LambdaResolverTree.cs: line 99
   at System.Dynamic.UpdateDelegates.UpdateAndExecuteVoid4<T0,T1,T2,T3>(CallSite site, T0 arg0, T1 arg1, T2 arg2, T3 arg3)
   at Resolver.LambdaResolver.BuildSql(OperationNode node) in LambdaResolverTree.cs: line 46
   at System.Dynamic.UpdateDelegates.UpdateAndExecuteVoid2<T0,T1>(CallSite site, T0 arg0, T1 arg1)
   at Resolver.LambdaResolver.ResolveQuery(Expression`1 expression) in LambdaResolverQuery.cs: line 18
   at LambdaSqlBuilder.SqlLam`1.And(Expression`1 expression) in SqlLam.cs: line 47
   at LambdaSqlBuilder.SqlLam`1.Where(Expression`1 expression) in SqlLam.cs: line 41
   at Tests.ExpressionTests.WhereMultipleBoolAndElse_Should_ReturnQuery() in ExpressionTests.cs: line 364


The only workaround I was able to do is add "== true" to both booleans, however 
if I only did 1 boolean, it works fine

Example..
query.Where(x => (x.IsActive || x.CreatedOn == date) && x.EmailAddress == 
"test@test.com");

This one works without issue

Original issue reported on code.google.com by lee...@leehull.com on 14 Feb 2014 at 2:09