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Set fixed storage size in yml #33

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Oct 8, 2019
Merged

Set fixed storage size in yml #33

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11 changes: 9 additions & 2 deletions src/optim_problems/opt.jl
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Original file line number Diff line number Diff line change
Expand Up @@ -361,8 +361,15 @@ function setup_opt_intertech_cap!(cep::OptModelCEP,
#Check for specific constraint that bounds the installed capacity of one technology to another
for tech in set["tech"]["all"]
if haskey(techs[tech].constraints,"cap_eq")
push!(cep.info,"CAP[$tech, 'new', node] = CAP[$(techs[tech].constraints["cap_eq"]), 'new', node] ∀ node, tech_{EUR-Cap-Cost out/in==0}")
@constraint(cep.model, [node=set["nodes"]["all"]], cep.model[:CAP][tech,"new",node] == cep.model[:CAP][techs[tech].constraints["cap_eq"],"new",node])
# With 'cap_eq_multiply', one can define the relationship between two technologies. This is useful for setting fixed storage hours: For a system
# with 4 hours of storage, set this value for 'bat_e' to '4.0' (assuming hourly delta t).
if haskey(techs[tech].constraints,"cap_eq_multiply")
cap_eq_multiply = techs[tech].constraints["cap_eq_multiply"] #parse(Float64,techs[tech].constraints["cap_eq_multiply"])
else
cap_eq_multiply = 1.0
end
push!(cep.info,"CAP[$tech, 'new', node] = CAP[$(techs[tech].constraints["cap_eq"]), 'new', node] *$cap_eq_multiply ∀ node, tech_{EUR-Cap-Cost out/in==0}")
@constraint(cep.model, [node=set["nodes"]["all"]], cep.model[:CAP][tech,"new",node] == cap_eq_multiply * cep.model[:CAP][techs[tech].constraints["cap_eq"],"new",node])
end
end
return cep
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