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Add probability theory
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Winterpuma committed Nov 27, 2021
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Завод производит 90% стандартных изделий. Имеется упрощённая проверка годности. Вероятность признаний стандартного изделия годным 0.98, нестандартного годным - 0.05. Какова вероятность того, что случайно выбранное изделие, признанное годным, является стандартным?
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Есть 20 станков. А - 10, В - 6, С - 4 изготавливают изделия соответствующей марки. Вероятность изготовления отличной детали на каждом 0,9, 0,8, 0,7. Найти процент изготовления отличных деталей.
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Есть 5 белых и 4 черных шара. Каждый ход - убираем шар. Через 4 хода оказалось, что 3 белых и 2 черных. Найти вероятность такого исхода.
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Студент знает 20 вопросов из 25. Какова вероятность сдать экзамен, если нужно ответить на хотя бы 2 из 3 вытащенных вопроса.
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Кидают три раза монету, узнать вероятность того, что за три раза хотя бы один раз выпадет орел.
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есть 5 черных шаров, 4 белых шара, каждую минуту вытаскивают по одному шару. Найти вероятность, что через 4 минуты останется 3 черных шара и 2 белых
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Найти вероятность того, что случайная величина X попадает в прямоугольник П = {-1 <= x <= 5 2 <= y <= 3}, если P{X < x, Y < y} = 2 - 2^(-x) - 2^(-y) - 2^(-x-y), при x > 0 && y > 0, 0 иначе.
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Две случайные величины X, Y распределены по экспоненциальному закону с параметрами 2, 5. Найти P{Y <= X}.
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X1 и X2 независимые случайные величины. Распределены по нормальному закону с мат ожиданиями 3 -2 и дисперсиями 3 4 соответственно. Найти вероятность P{X2 < X1 + 5}.
3 changes: 3 additions & 0 deletions 5-semester/5-probability-theory/Exam/Practice/Tickets/2/4.txt
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Два стрелка делают по одному выстрелу в общую мишень. Вероятность попадания первого 0.7. Для второго 0.8.
Составьте ряд распределения для величины Z = X - Y, где X-количество попаданий первого. Y-второго.
Найдите MZ,DZ.
2 changes: 2 additions & 0 deletions 5-semester/5-probability-theory/Exam/Practice/Tickets/2/5.txt
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Есть две девочки, у одной из них 4 чупса и 4 сникерса, у второй 3 сникерса и 5 чупсов (цифры примерные).
Найти с использованием критерия максимальной вероятности, у какой из них будет больше чупсов если они неглядя махнулись по одной конфете.
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Дана большая партия деталей, в ней 1% брака, сколько минимум нужно взять деталей, чтобы в твоей выборке вероятность того, что есть хотя бы одна бракованная деталь была 95%.
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6 changes: 6 additions & 0 deletions 5-semester/5-probability-theory/Exam/Practice/Tickets/2/7.txt
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у = х^2 - 2x

найти плотность распределения у, если плотность распределения

х = {0, если х < 0
{e^(-x), если х > 0
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