SUM подправлено - 2 #2
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korzio
commented
Mar 4, 2018
| agg = (arguments.length === 0) ? (agg) : (agg + arguments[0]); | ||
| return innerAgg; | ||
| }; | ||
| innerAgg.valueOf = function() { |
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Как вариант, в valueOf можно обнулять значение agg
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