If else

[champaksworldcreate]

1. Find the max of three numbers
2. Check for a leap year
3. Solve a Quadratic Equation
4. Check the type of a Triangle. Is triangle possible, Equilateral, Isosceles, Scalene and Right Angled
5. Check for pass, fail and division given marks in 3 subjects. 40 is passing marks. 3rd division >=40 <50, >=50 <60 2nd, >=60 1st.
6. Convert 0-9 digits to words
7. Find the days in month given the month no and year
8. Find the quadrant given the angle
9. Solve the above programs using ternary operator
10. Solve the above programs using switch

[piyushcodevns]

Understanding Leap Year

Every year has 365.2425 days which is approximately 1/4th of dy. In 4 years this will become 1 day. Therefore after every 4 years we add an extra day.

1. Normal year 365 days and Feb=28 days
2. Leap year 366 days and Feb=29 days.

Simple logic have a leap year every 4th year. If year is divisible by 4 days=366, else days= 365.

Some extra time still needs adjustment

Year div by 400 div by 4 div by 100 Result
2025 No No No Not leap year
2000 Yes Yes Yes Leap year
2024 No Yes No Leap Year
1900 No Yes Yes Not leap year

if((year % 400==0) ||(year % 4==0 && year % 100!=0))
Leap Year
else
Not Leap Year