decimal_to_octal return

[afeiguo]

the return code is wrong for big number, e.g.:

print("{0:g}".format(float(1000000001.0)))

the return is 1e+09, not '1000000001'

[afeiguo]

the return code is wrong for big number, e.g.:

print("{0:g}".format(float(1000000001.0)))

the return is 1e+09, not '1000000001'

coding should change:

return "{0:g}".format(float(octal))

to

return str(int(octal))

[blaxii]

If you want you can do:

def decimal_to_octal(num):

"""Convert a Decimal Number to an Octal Number."""
calcul = ""
while num > 0:
    rest = num % 8
    num = num // 8
    calcul = str(rest) + calcul
return int(calcul)

As I see your code is too complex for the program you want to do.

[cclauss]

num, rest = divmod(num, 8)

[onlinejudge95]

The issue has been fixed here #1482. Hence closing the issue.