ISFORMULA() not recognized and throws exception. Steps to reproduce. Create a new spreadsheet. In the cell A1 enter
The result should be FALSE and is valid. Try loading the spreadsheet in PhpSpreadsheet and read cells like this:
$spreadsheet = \PhpOffice\PhpSpreadsheet\IOFactory::load($filename);
$rows = $spreadsheet->getSheet($sheet)->toArray();
Results in an exception:
Sheet1!A1 -> undefined named range / function '_xlfn.ISFORMULA'
Related: PHPOffice/PHPExcel#1136
formula_test.xlsx