Authorization header #284
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How can you add default authorization header to domain context requests? |
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Replies: 2 comments
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The most straightforward way would be to create your own DomainClientFactory and overriding the CreateChannelFactory/CreateBinding method or similar in order to setup a WCF IClientMessageInspector which adds a header (by first retreiving a HttpRequestMessageProperty from the Message's Properties) I found a similar WCF example (I think) in VB and quite long at http://ericphan.net/blog/2010/6/3/adding-custom-http-header-to-all-wcf-requests.html and on stackoverflow https://stackoverflow.com/a/7165593 |
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I updated my blazor wasm sample pr to use oauth token authentication.
…________________________________
From: Daniel Svensson ***@***.***>
Sent: Friday, May 21, 2021 8:00:55 AM
To: OpenRIAServices/OpenRiaServices ***@***.***>
Cc: dsoltesz ***@***.***>; Author ***@***.***>
Subject: Re: [OpenRIAServices/OpenRiaServices] Authorization header (#284)
The most straightforward way would be to create your own DomainClientFactory and overriding the CreateChannelFactory/CreateBinding method or similar in order to setup a WCF IClientMessageInspector<https://docs.microsoft.com/en-us/dotnet/framework/wcf/extending/how-to-inspect-or-modify-messages-on-the-client> which adds a header (by first retreiving a HttpRequestMessageProperty from the Message's Properties)
I found a similar WCF example (I think) in VB and quite long at http://ericphan.net/blog/2010/6/3/adding-custom-http-header-to-all-wcf-requests.html and on stackoverflow https://stackoverflow.com/a/7165593
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The most straightforward way would be to create your own DomainClientFactory and overriding the CreateChannelFactory/CreateBinding method or similar in order to setup a WCF IClientMessageInspector which adds a header (by first retreiving a HttpRequestMessageProperty from the Message's Properties)
I found a similar WCF example (I think) in VB and quite long at http://ericphan.net/blog/2010/6/3/adding-custom-http-header-to-all-wcf-requests.html and on stackoverflow https://stackoverflow.com/a/7165593