[LIS-WDFT-APR2023] Henrique Ortiz

index.js

@@ -1,7 +1,58 @@
 // Iteration 1: Names and Input
+let hacker1 = "Henrique";
+console.log("The driver's name is", hacker1);
 
+let hacker2 = "Guy";
+console.log("The navigator's name is", hacker2);
 
 // Iteration 2: Conditionals
+/*
+2.1. Depending on which name is longer, print:
+- The driver has the longest name, it has XX characters. or
+- It seems that the navigator has the longest name, it has XX characters. or
+- Wow, you both have equally long names, XX characters!.*/
+
+console.log(hacker1.length)
 
-
+if (hacker1.length > hacker2.length) {
+    console.log(`The driver has the longest name, it has ${hacker1.length} characters`);
+}
+else if (hacker1.length < hacker2.length) {
+    console.log(`It seems that the navigator has the longest name, it has ${hacker2.length} characters.`);
+}
+else {
+    console.log(`Wow, you both have equally long names ${hacker1.length} characters!.`);
+}
 // Iteration 3: Loops
+/*3.1 Print the characters of the driver's name, separated by space, and in capital letters, i.e., "J O H N".*/
+
+let driver = ""
+for (i = 0; i < hacker1.length; i++) {
+    driver = driver + hacker1[i] + " ";
+}
+console.log(driver.toUpperCase());
+
+//3.2 Print all the characters of the navigator's name, in reverse order, i.e., "nhoJ".
+
+let reversed =  "";
+for (let nameReversed of hacker2) {
+    reversed = nameReversed + reversed;
+}
+console.log(reversed);
+
+/*3.3 Depending on the lexicographic order of the strings, print:
+
+The driver's name goes first.
+Yo, the navigator goes first definitely.
+What?! You both have the same name?*/
+
+
+if (hacker2.localeCompare(hacker1)===1) {
+    console.log("The driver's name goes first.");
+}
+else if (hacker1.localeCompare(hacker2)===1) {
+    console.log("Yo, the navigator goes first definitely.");
+}
+else {
+    console.log("What?! You both have the same name?");
+}