The bug here is a bit subtle, but perhaps best illustrated with
the included test case:
```
function f32579(x::Int64, b::Bool)
if b
x = nothing
end
if isa(x, Int64)
y = x
else
y = x
end
if isa(y, Nothing)
z = y
else
z = y
end
return z === nothing
end
```
The code just after SSA conversion looks like:
```
2 1 ─ goto #3 if not _3
3 2 ─ %2 = Main.nothing::Core.Compiler.Const(nothing, false)
5 3 ┄ %3 = φ (#2 => %2, #1 => _2)::Union{Nothing, Int64}
│ %4 = (%3 isa Main.Int64)::Bool
└── goto #5 if not %4
6 4 ─ %6 = π (%3, Int64)
└── goto #6
8 5 ─ %8 = π (%3, Nothing)
10 6 ┄ %9 = φ (#4 => %6, #5 => %8)::Union{Nothing, Int64}
│ %10 = (%9 isa Main.Nothing)::Bool
└── goto #8 if not %10
11 7 ─ %12 = π (%9, Nothing)
└── goto #9
13 8 ─ %14 = π (%9, Int64)
15 9 ┄ %15 = φ (#7 => %12, #8 => %14)::Union{Nothing, Int64}
│ %16 = (%15 === Main.nothing)::Bool
└── return %16
```
Now, we have special code in SROA (despite it not really being an
SROA transform) that looks at `===` and replaces
it by a nest of phis of booleans. The reasoning for this transform
is that it eliminates a use of a value where we only care about the
type and not the content, thus making it more likely that the value
will subsequently be eligible for SROA. In addition, while it goes
along resolving which values feed into any particular phi, it
accumulates and type conditions it encounters along the way.
Thus in the example above, something like the following happens:
- We look at %14, which πs to %9 with an Int64 constraint, so we only
consider the #4 predecessor for %9 (due to the constraint), until
we get to %3, where we again only consider the #1 predecessor,
where we find the argument (of type Int64) and conclude the result
is always false
- Now we pop the next item of the stack from our original phi, look
at %12, which πs to %9 with a Nothing constraint.
At this point we used to terminate the search because we already looked
at %9. However, crucially, we looked at %9 only with an Int64 constraint,
so we missed the fact that `nothing` was in fact a possible value for this
phi. The result was a missing entry in the generated phi node:
```
1 ─ goto #3 if not b
2 ─ %2 = Main.nothing::Core.Compiler.Const(nothing, false)
3 ┄ %3 = φ (#1 => false)::Bool
│ %4 = φ (#2 => %2, #1 => _2)::Union{Nothing, Int64}
│ %5 = (%4 isa Main.Int64)::Bool
└── goto #5 if not %5
4 ─ %7 = π (%4, Int64)
└── goto #6
5 ─ %9 = π (%4, Nothing)
6 ┄ %10 = φ (#4 => %3, #5 => %3)::Bool
│ %11 = φ (#4 => %7, #5 => %9)::Union{Nothing, Int64}
│ %12 = (%11 isa Main.Nothing)::Bool
└── goto #8 if not %12
7 ─ goto #9
8 ─ nothing::Nothing
9 ┄ %16 = φ (#7 => %10, #8 => %10)::Bool
└── return %16
```
(note the missing #2 predecessor in phi node %3), which would result
in an undefined value at runtime, though in this case LLVM would
have taken advantage of that to just return 0:
```
define i8 @julia_f32579_16051(i64, i8) {
top:
; @ REPL[1]:15 within `f32579'
ret i8 0
}
```
Compare this now to the optimized IR with this patch:
```
1 ─ goto #3 if not b
2 ─ %2 = Main.nothing::Core.Compiler.Const(nothing, false)
3 ┄ %3 = φ (#2 => true, #1 => false)::Bool
│ %4 = φ (#2 => %2, #1 => _2)::Union{Nothing, Int64}
│ %5 = (%4 isa Main.Int64)::Bool
└── goto #5 if not %5
4 ─ %7 = π (%4, Int64)
└── goto #6
5 ─ %9 = π (%4, Nothing)
6 ┄ %10 = φ (#4 => %3, #5 => %3)::Bool
│ %11 = φ (#4 => %7, #5 => %9)::Union{Nothing, Int64}
│ %12 = (%11 isa Main.Nothing)::Bool
└── goto #8 if not %12
7 ─ goto #9
8 ─ nothing::Nothing
9 ┄ %16 = φ (#7 => %10, #8 => %10)::Bool
└── return %16
```
The %3 phi node has its missing entry and the generated LLVM code
correctly returns `b`:
```
define i8 @julia_f32579_16112(i64, i8) {
top:
%2 = and i8 %1, 1
; @ REPL[1]:15 within `f32579'
ret i8 %2
}
```