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''' | ||
Given a non-negative integer num, repeatedly add all its digits until the result has only one digit. | ||
Example: | ||
Input: 38 | ||
Output: 2 | ||
Explanation: The process is like: 3 + 8 = 11, 1 + 1 = 2. | ||
Since 2 has only one digit, return it. | ||
Follow up: | ||
Could you do it without any loop/recursion in O(1) runtime? | ||
''' | ||
class Solution: | ||
def addDigits(self, num: int) -> int: | ||
if num < 10: | ||
return num | ||
return num % 9 if num % 9 != 0 else 9 |