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Missing Number in the array
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''' | ||
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. | ||
Example 1: | ||
Input: [3,0,1] | ||
Output: 2 | ||
Example 2: | ||
Input: [9,6,4,2,3,5,7,0,1] | ||
Output: 8 | ||
Note: | ||
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity? | ||
''' | ||
class Solution: | ||
def missingNumber(self, nums: List[int]) -> int: | ||
res = 0 | ||
for i in range(len(nums) + 1): | ||
res ^= i | ||
if i < len(nums): | ||
res ^= nums[i] | ||
return res |