js-flatten and @:expose

[andyli]

Given a class foo.Foo with @:expose, I suppose it is accessible from external by foo.Foo. However with -D js-flatten, it is exposed as foo_Foo.
Example:

package foo;
@:expose
class Foo {
    static function main():Void {}
}

Gives:

(function ($hx_exports) { "use strict";
var foo_Foo = $hx_exports.foo_Foo = function() { };
foo_Foo.main = function() {
};
foo_Foo.main();
})(typeof window != "undefined" ? window : exports);

I can't find a way to use -D js-flatten while maintaining the exposed package object and name. Adding @:native("foo.Foo") gives exactly the same result.

[deltaluca]

If you use @:expose("foo.Foo") instead you will get what you want.

I'm not 100% sure whether to say exposing as foo_Foo when using js-flatten is a bug or not.

[andyli]

Didn't know that @:expose("foo.Foo"). It works :)
However I still think that -D js-flatten should change only internal representation, just like any optimization.

[Simn]

It's a tough call, but I'm with Andy on this one.