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Decide #4281's eleven open depth-five connector residues: exact minima 30, 35, 35 (m=5), 30, 36, 36, 36 (m=6), 35, 42 (m=7), 40, 40 (m=8) (no new κ) - #4418
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Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
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Summary
This adds
research/depth5-connector-residues/. It decides exactly the eleven depth-five chain-connector pairs(m, c)with5 ≤ m ≤ 8that #4281 (petalas) left as "a search failure, not a bound". It closes #4281's open question and #4341's.Claim type: exhaustive finite computation for the lower bounds and checked certificates for the upper bounds. No new κ.
Result
With #4281's rows, the depth-five minimum is now known for every
cat2 ≤ m ≤ 20.c ≡ −1. Atm = 4..7, the residue−1misses5m: it costs7matm = 4, 5and6matm = 6, 7.m = 8. Every residue attains5mthere.Method
Calls
landkcommute when|l − k| ≥ 2. So the interval counts of #4281's Lemma 1 depend only on three things:For one count vector,
residues.cenumerates exactly that data and returns every reachablec, with a witness for each. Lengths not divisible bymare excluded by Lemma 1.Cross-checks. The decider's minima over all count vectors equal the exhaustive BFS minima: 16 at
m = 2; 24, 24 atm = 3; 28, 24, 28 atm = 4, including the residue-dependent case.Lower bounds. Complete runs over every count vector give:
ccbut 6Witnesses. All eleven are verified by the unitriangular product and by literal replays with random noncommuting 2×2 maps.
(7,6),(8,5)and(8,7)were found by a simple annealer.Evidence
verify.py, standard library, takes about 90 s:m = 2andm = 3below 24 calls;residues.c, by SHA256;The C runs are local evidence that CI does not repeat. The
m = 7balanced run took 93 s.Head:
f87bec70596b2e34d641fd70a0fde281c94d5eaf.Not covered
m > 20.Task and overlap
connector-alphabet-change, refined, priority revision 7.12fa8c5c844be21bfefb38a19503fbd867a11244.Credit
The model, Lemma 1 and #4281's witnesses are Nick Petalas's, building on #4249 and #4263. Prepared by Ryanson Jonathan with substantial Claude Code (Claude Opus 5.5) assistance. Apache-2.0.
🤖 Generated with Claude Code