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Consider :has()
as a standard pseudo-class if ExtendedCss usage is not forced by #?#
rule marker
#43
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Resolution: Done
Status: Closed
Version: Safari v1.11.10
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Resolution: Fixed
Status: Resolved
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Resolution: Done
Version: Safari v1.11.10
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…not forced by `#?#` rule marker. AG-17273 AdguardTeam/SafariConverterLib#43 Squashed commit of the following: commit 37b13bd Author: Slava Leleka <v.leleka@adguard.com> Date: Wed Apr 5 19:40:04 2023 +0300 fix version parsing commit 829fdd7 Author: Slava Leleka <v.leleka@adguard.com> Date: Wed Apr 5 16:45:32 2023 +0300 add comment to changelog commit 6bce013 Author: Slava Leleka <v.leleka@adguard.com> Date: Wed Apr 5 16:44:14 2023 +0300 add changelog commit 2c167f2 Author: Slava Leleka <v.leleka@adguard.com> Date: Tue Apr 4 10:45:56 2023 +0300 update safari-converter-lib to v2.0.39 commit 76539e9 Author: Slava Leleka <v.leleka@adguard.com> Date: Mon Apr 3 17:28:00 2023 +0300 parse safariVersion as float for convertRulesToJson()
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:has() pseudo-class has native implementation
https://developer.mozilla.org/en-US/docs/Web/CSS/:has
and since ExtendedCss v2 release the rule with
##
marker and:has()
should not be considered as ExtendedCssbut :has() pseudo-class should be considered as ExtendedCss if the rule marker is
#?#
https://github.com/AdguardTeam/ExtendedCss#extended-css-has
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