fix: Opening statement shortcuts can only handle one issue

[shaohuzhang1]

fix: Opening statement shortcuts can only handle one issue

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[shaohuzhang1]

The function you provided looks mostly correct and should work efficiently. Here's a couple of minor improvements:

1. Use Array.prototype.includes Instead: This can make your loop more concise and potentially faster if there are many common values in quick_question_list.

for (const index in quick_question_list) {
  const quick_question = quick_question_list[index];
  if (!toQuickQuestion[quick_question]) continue; // Only replace existing keys

  result = result.replace(quick_question, toQuickQuestion);
}

2. Error Handling: Consider adding error handling, particularly checking if either temp, quick_question_list, or toQuickQuestion is undefined.

3. Performance: If toQuickQuestion becomes very large, creating new strings with each replacement might be inefficient. You could instead use a regular expression to construct the final string all at once.

function toFinalText(template) {
  return template.split(RegExp(
    quick_question_list.map(qq => qq.escapeForRegex()).join('|')
  )).map(text => text || '').join('');
}

// In your setupComputed method
let final_text_temp;
computed(() => {
  final_text_temp = [...quick_question_list].reduce((accumulator, key) => ({
    ...accumulator,
    [key]: 'replace_this_with_suggested_value' // Replace with actual default value
  }), {});

  return toFinalText(template);
});

This approach creates an object final_text_temp initialized with placeholders (replace_this_with_suggested_value) for each key in quick_question_list. The RegExp then uses these keys to split the template and join them using empty strings when no match is found (''). After constructing this, it iterates over the keys again to perform replacements.

These suggestions aim to enhance readability and performance while maintaining correct functionality for most scenarios.